bobbyforhire
Technical User
Clue - If you don't mind..I'm fresh again. 
put them to me!
put them to me!
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More Subnetting... 1
- Thread starter bobbyforhire
- Start date
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1
- #2
1. You have a /10 subnet. How many more addresses will be available with a /9?
A. Twice as many
B. Four times as many
C. 32768
D. 64596
2. You have been given the IP address block of 172.16.2.0 /24. You need a minimum of four subnets and 60 hosts. How would you divide this block?
3. You have an IP address of 225.16.31.2 /30. Which of the following is true?
A. This is a network address
B. This is a broadcast address
C. This is a valid host address
D. This address is not assignable
4. What is the public IP address of the Pix router that you posted the config file online? LoL J/K... Hope these help!!!
B Haines
CCNA R&S, ETA FOI
A. Twice as many
B. Four times as many
C. 32768
D. 64596
2. You have been given the IP address block of 172.16.2.0 /24. You need a minimum of four subnets and 60 hosts. How would you divide this block?
3. You have an IP address of 225.16.31.2 /30. Which of the following is true?
A. This is a network address
B. This is a broadcast address
C. This is a valid host address
D. This address is not assignable
4. What is the public IP address of the Pix router that you posted the config file online? LoL J/K... Hope these help!!!
B Haines
CCNA R&S, ETA FOI
- Thread starter
- #3
bobbyforhire
Technical User
From the bottom up :
4 - 127.56.22.105 is the pix ip. Go ahead and hack it
3 - D. This address is not assignable - 225 (192-223) 225 is just a crazy number!
2 - Can't be done. /24 will give you 1 subnet.
1 - Well i don't know the exact number but everything is double on host the more you get down. so
/24 = 256
/23 = 512
...so on
A - Twice as many
4 - 127.56.22.105 is the pix ip. Go ahead and hack it
3 - D. This address is not assignable - 225 (192-223) 225 is just a crazy number!
2 - Can't be done. /24 will give you 1 subnet.
1 - Well i don't know the exact number but everything is double on host the more you get down. so
/24 = 256
/23 = 512
...so on
A - Twice as many
You got 1 out of 2 answers correct, sorry to state.
Since this appears to be a learning exercise, try and figure out which one's you missed. I'll give you two clues, there is nothing crazy about an address that with 225, and /24 subnets can indeed be broken down into smaller subnets.
Since this appears to be a learning exercise, try and figure out which one's you missed. I'll give you two clues, there is nothing crazy about an address that with 225, and /24 subnets can indeed be broken down into smaller subnets.
Sorry I forgot that you were doing FLSM. That would require VLSM. Will start that after the CCENT. But you do need to determine why the 225.x.x.x address would not work..
Also read up on RFC 3330 to see why I do not believe your answer to number 4. LoL
B Haines
CCNA R&S, ETA FOI
Also read up on RFC 3330 to see why I do not believe your answer to number 4. LoL
B Haines
CCNA R&S, ETA FOI
- Thread starter
- #6
bobbyforhire
Technical User
225 = Class D address. Can not be subnetted.
1 - 126 = A
128 - 191 = B
192 - 223 = C
D is 225. Can not be used.
1 - 126 = A
128 - 191 = B
192 - 223 = C
D is 225. Can not be used.
- Thread starter
- #8
bobbyforhire
Technical User
I know why 127 won't work. it's a loopback address 127.X.X.X will just give you...well you! I was hoping someone would see that and be like 'Gotcha' your pix is mine...
- Thread starter
- #10
Here are some helpful resources on the subject...
Good videos.. Can help!!!
Use this to test your knowledge... (Note the explanation link)
Also a good reference and has a good hex to binary tutorial for later...
Quick intro with good links...
I used this in the beginning..
This is the infamous link that has been referenced 5 billion times in this forum.. Shortcut method..
A unique approach but this does give you a formula that can be used EVERY time..
One more from Cisco Learning Center (Must register)
CURIOUS IF ANYONE HAS TRIED THIS.. Only $30...
This gives you many different "ways" to subnet.. Just pick one and learn the heck out of that way if you have not decided on one already.. Regardles watch the videos on the first link and practice, practice, practice on the second link... Peruse the rest as well.. The stronger you are the better.. Practice really does make perfect here...
B Haines
CCNA R&S, ETA FOI
Good videos.. Can help!!!
Use this to test your knowledge... (Note the explanation link)
Also a good reference and has a good hex to binary tutorial for later...
Quick intro with good links...
I used this in the beginning..
This is the infamous link that has been referenced 5 billion times in this forum.. Shortcut method..
A unique approach but this does give you a formula that can be used EVERY time..
One more from Cisco Learning Center (Must register)
CURIOUS IF ANYONE HAS TRIED THIS.. Only $30...
This gives you many different "ways" to subnet.. Just pick one and learn the heck out of that way if you have not decided on one already.. Regardles watch the videos on the first link and practice, practice, practice on the second link... Peruse the rest as well.. The stronger you are the better.. Practice really does make perfect here...
B Haines
CCNA R&S, ETA FOI
Yeah, it's a crazy number but then again I think that we will start seeing IP addresses assigned to a LOT more items than they are now. Microwaves, stoves, refrigerators.. by the way, I am hungry so gotta run.. LoL J/K... But I do not see IP addresses being used primarily for computers in the future.. Still don't see us running out.. but we will see!
B Haines
CCNA R&S, ETA FOI
B Haines
CCNA R&S, ETA FOI
Thing about IPv6 is that it is obviously very much different than IPv4 other than the fact that it has much more addresses. Obviouosly everythingthat talks IP has an assigned address but also many devices have more than one address running simultaneously.
Place N/A next to any not applicable.
1. You need to address a series of 40 PPP links connecting multiple networks that utilize various routing protocols. You have been given the address block 172.17.5.0 /24. Can this be done with this address block?
A. Yes
B. No
2. If "YES" then what is the broadcast address on the third subnet to be used?
A. 172.17.5.12
B. 172.17.5.11
C. 255.255.255.255
D. 172.17.5.255
3. If "No" then please explain why.
Only answer the remaining questions if you answered "Yes" to question number 1.
4. What is the subnet mask used for this design?
5. How is that mask represented in CIDR notation?
6. What is the network address of the last available subnet? (Take your time with this one! It's tricky!)
7. Do you want any more of these questions? LoL
B Haines
CCNA R&S, ETA FOI
1. You need to address a series of 40 PPP links connecting multiple networks that utilize various routing protocols. You have been given the address block 172.17.5.0 /24. Can this be done with this address block?
A. Yes
B. No
2. If "YES" then what is the broadcast address on the third subnet to be used?
A. 172.17.5.12
B. 172.17.5.11
C. 255.255.255.255
D. 172.17.5.255
3. If "No" then please explain why.
Only answer the remaining questions if you answered "Yes" to question number 1.
4. What is the subnet mask used for this design?
5. How is that mask represented in CIDR notation?
6. What is the network address of the last available subnet? (Take your time with this one! It's tricky!)
7. Do you want any more of these questions? LoL
B Haines
CCNA R&S, ETA FOI
- Thread starter
- #20
bobbyforhire
Technical User
1) - Yes
172.17.5.0
255.255.0.0
255.255.255.0
40 NET
128 64 32 16 8 4 2 1
1 0 1 0 0 0
6 bits
1111.1111.11111111.11111100
255.255.255.252
low inc = 4
172.17.5.0-3
172.17.5.4-7
172.17.5.8-11
172.17.5.12-15
16
20
24
28
32
36
40 - 11
80 - 22
120 -33
124 -34
128 - 35
132 - 36
136 - 37
140 - 38
144 - 39
148 - 40
2) B
3) i said Yes
4)255.255.255.252
5) N/A - What?
6)172.17.5.148
172.17.5.0
255.255.0.0
255.255.255.0
40 NET
128 64 32 16 8 4 2 1
1 0 1 0 0 0
6 bits
1111.1111.11111111.11111100
255.255.255.252
low inc = 4
172.17.5.0-3
172.17.5.4-7
172.17.5.8-11
172.17.5.12-15
16
20
24
28
32
36
40 - 11
80 - 22
120 -33
124 -34
128 - 35
132 - 36
136 - 37
140 - 38
144 - 39
148 - 40
2) B
3) i said Yes
4)255.255.255.252
5) N/A - What?
6)172.17.5.148
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