I have quintum (fxo port) registered as sip extension on IP Office 500. From ip office make call to quintum was success. But if pstn call to fxo (quintum), i can't call to extension avaya. The log show anonymous@"ip quintum". Can avaya allow call from anonymous ?
Here the log :
4728834mS SIP Rx: UDP 61.247.38.227:5063 -> 202.80.118.53:5060
INVITE sip:600@202.80.118.53 SIP/2.0
Call-ID: call-71851B99-D947-2E10-011C-11@61.247.38.227
Contact: <sip:anonymous@61.247.38.227:5063>
Content-Length: 274
Content-Type: application/sdp
CSeq: 1 INVITE
Expires: 180
From: <sip:anonymous@202.80.118.53>;tag=c0a80142-1a
Max-Forwards: 70
Session-GUID: 878993717-895902817-1711276066-0
Supported: 100rel
To: <sip:600@202.80.118.53>
User-Agent: Quintum/1.0.0 SN/0030E1207385 SW/P107-09-00
Via: SIP/2.0/UDP 61.247.38.227:5063;branch=z9hG4bK-tenor-c0a8-0142-0053
Quintum: 0c01030b0235301301000f0b413036322d323037333835
v=0
o=Quintum 10 10 IN IP4 61.247.38.227
s=VoipCall
c=IN IP4 61.247.38.227
t=0 0
m=audio 10254 RTP/AVP 4 18 101
c=IN IP4 61.247.38.227
a=rtpmap:4 G723/8000/1
a=ptime:30
a=fmtp:18 annexb=yes
a=rtpmap:18 G729/8000/1
a=rtpmap:101 telephone-event/8000/1
a=sendrecv
Here the log :
4728834mS SIP Rx: UDP 61.247.38.227:5063 -> 202.80.118.53:5060
INVITE sip:600@202.80.118.53 SIP/2.0
Call-ID: call-71851B99-D947-2E10-011C-11@61.247.38.227
Contact: <sip:anonymous@61.247.38.227:5063>
Content-Length: 274
Content-Type: application/sdp
CSeq: 1 INVITE
Expires: 180
From: <sip:anonymous@202.80.118.53>;tag=c0a80142-1a
Max-Forwards: 70
Session-GUID: 878993717-895902817-1711276066-0
Supported: 100rel
To: <sip:600@202.80.118.53>
User-Agent: Quintum/1.0.0 SN/0030E1207385 SW/P107-09-00
Via: SIP/2.0/UDP 61.247.38.227:5063;branch=z9hG4bK-tenor-c0a8-0142-0053
Quintum: 0c01030b0235301301000f0b413036322d323037333835
v=0
o=Quintum 10 10 IN IP4 61.247.38.227
s=VoipCall
c=IN IP4 61.247.38.227
t=0 0
m=audio 10254 RTP/AVP 4 18 101
c=IN IP4 61.247.38.227
a=rtpmap:4 G723/8000/1
a=ptime:30
a=fmtp:18 annexb=yes
a=rtpmap:18 G729/8000/1
a=rtpmap:101 telephone-event/8000/1
a=sendrecv