form.release() question

[R17]

i have two forms, form1 and form2. my form1 contains a command button with click event "DO FORM form2".

in my form 2 i have an option group and 2 command buttons "OK" and "CANCEL".

i have this in my click event for "OK".

Thisform.Release() && release my form2
Thisform.Savemode() && method i created in form1

whenever i run my form, i get an error that it cannot find my method savemode.

my question is, shouldn't my form1 be "activated" after i release my second form? if i do another DO FORM form1 after Thisform.Release(), i'm having 2 instances of my form, that is i have to click "X" twice to close the form.

pls enlighten me on this matter..

 

[craigsboyd]

It sounds like you have the thisform.savemode() being called from your form2 that you have just released...also, I am thinking that savemode() is a method of form1 not form2 so calling it from inside form2 doesn't do you any good since the thisform is form2, not form1.

Solution---
Put the follwoing in your command button on form1:

do form2 to lOkclicked

if lokclicked
thisform.savemode()
endif


In the form2 load event:
Public lReturn
lReturn = .f.

In the form2 ok button click event:
lReturn = .t.

In the form2 unload event

Return(lReturn) Slighthaze = NULL

 

[ramani]

HI

You can refer form1 in form2.. with object reference.. i.e.
Form1.SaveMode()

In order to make this work..
DO FORM form1 NAME form1

In form2.. you can refer form1 with reference Form1.SaveMode instead of ThisForm.SaveMode()

ramani
(Subramanian.G),FoxAcc, ramani_g@yahoo.com

 

[SGLong]

R17,

You may also have a conflict with the form name. When you create the first form it's automatically named "FORM1". When you create the second form it's also named "FORM1". I always change my form names - i.e. "FRM_ADD_CUSTOMER" and "FRM_PRINT_HISTORY". It also makes things easier to debug because you'll know exactly which form caused the problem.

Steve

 

[fruityBoy]

Hi you could pass the form as an object reference eg:

do form2 with this

in the init of form2

lparam ;
localler

this.caller_o = localler

in the release:
local ;
localler

localler = this.caller_o
localler.savemode()

 

[R17]

thanks!

i figured it out myself, i did the same thing as ramani. but i'll try all your suggestions. thanks again!