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XSLT to group similar elements?

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capitano

capitano

Programmer
Jul 30, 2001
88
US
I have a pile of XML like the below. What I want to do is group all the <li> elements together under a new parent, call it <ul>. I am trying to find a way to do this with XSLT, but am having problems. It seems like XSLT would be a perfect candidate for such a re-grouping of elements, but I can't figure it out. Thanks for any help!

<root>
<first>
<description>A list of trees follows</description>
<li>Fir</li>
<li>Maple</li>
<li>Pine</li>
</first>
<second>
<description>A list of cars follows</description>
<li>Mazda</li>
<li>Honda</li>
<li>Toyota</li>
</second>
</root>

I have tried using the XSLT Axis notation &quot;following-sibling&quot;, but this doesn't produce the results I'm hoping for. I have tried this:

<?xml version=&quot;1.0&quot;?>
<xsl:stylesheet version=&quot;1.0&quot; xmlns:xsl=&quot; <xsl:eek:utput method=&quot;xml&quot; indent=&quot;yes&quot; />

<xsl:template match=&quot;/ | * | @*&quot;>
<xsl:copy>
<xsl:apply-templates select=&quot;* | @* | text()&quot;/>
</xsl:copy>
</xsl:template>

<xsl:template match=&quot;li&quot;>
<ul>
<xsl:for-each match=&quot;./following-sibling::li&quot;>
<li><xsl:value-of select=&quot;.&quot;/>
</xsl:for-each>
</ul>
</xsl:template>

The above XSLT seems to group all the <li> elements throughout the entire XML document indiscriminantly. I'm really struggling with this. Any ideas? Thanks!
 
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Code: 
<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<xsl:stylesheet
	xmlns:xsl=&quot;[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform&quot;[/URL]
	version=&quot;1.0&quot;>

<xsl:template match=&quot;li&quot;>
<li>
        <xsl:value-of select=&quot;.&quot;/>
</li>
</xsl:template>

<xsl:template match=&quot;/&quot;>
<ul>
	<xsl:apply-templates select=&quot;//li&quot; />
</ul>
</xsl:template>
</xsl:stylesheet>

-pete
 
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Thanks. After implementing your suggestion, I get the following:

<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<ul>
<li>Fir</li>
<li>Maple</li>
<li>Pine</li>
<li>Mazda</li>
<li>Honda</li>
<li>Toyota</li>
</ul>

In fact, what I was hoping for was:

<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<root>
<first>
<description>A list of trees follows</description>
<ul>
<li>Fir</li>
<li>Maple</li>
<li>Pine</li>
</ul>
</first>
<second>
<description>A list of cars follows</description>
<ul>
<li>Mazda</li>
<li>Honda</li>
<li>Toyota</li>
</ul>
</second>
</root>

So... any other ideas? Thanks for the help so far. I feel a solution must close by!
 
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>> Thanks. After implementing your suggestion, I get the following:

Yep. Sorry i didn't understand what your goal was. [sadeyes]

-pete
 
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Code: 
<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<xsl:stylesheet
	xmlns:xsl=&quot;[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform&quot;[/URL]
	version=&quot;1.0&quot;>
	
<xsl:output omit-xml-declaration=&quot;no&quot;
             method=&quot;html&quot;
             doctype-public=&quot;-//W3C//DTD XHTML 1.0 Strict//EN&quot;
             doctype-system=&quot;[URL unfurl="true"]http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd&quot;[/URL]
	     indent=&quot;no&quot; encoding=&quot;UTF-8&quot; />

<xsl:template match=&quot;li&quot;>
	<xsl:copy-of select=&quot;.&quot; />
</xsl:template>

<xsl:template match=&quot;description&quot;>
	<xsl:copy-of select=&quot;.&quot; />
</xsl:template>

<xsl:template match=&quot;*&quot;>
	<xsl:copy>
	<xsl:apply-templates select=&quot;description&quot; />
	<ul>
	<xsl:apply-templates select=&quot;li&quot; />
	</ul>
	</xsl:copy>
</xsl:template>

<xsl:template match=&quot;/&quot;>
	<xsl:apply-templates select=&quot;root/*&quot; />
</xsl:template>
</xsl:stylesheet>

-pete
 
Upvote 0 Downvote
Perfect example and a solution. I have a similar problem - suppose that I have the following xml file and the result should be the second one. Is this possible in xslt (grouping similar elemets if they have the same attribute name value.

<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<body>
<li name='one'>Fir</li>
<li name='one'>Map</li>
<li name='two'>Pine</li>
<li name='two'>Mazda</li>
<li name='one'>Honda</li>
<li name='tree'>Toyota</li>
</body>


output as:

<?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot; ?>
<body>
<ul>
<li>Fir</li>
<li>Map</li>
<li>Honda</li>
</ul>
<ul>
<li>Pine</li>
<li>Mazda</li>
</ul>
<ul>
<li>Toyota</li>
</ul>
</body>
 
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