XSLT queries ... <xsl:copy-of>, etc.

[arvin21]

GIVEN:

<xsl:output omit-xml-declaration=&quot;no&quot; encoding=&quot;utf-8&quot; indent=&quot;no&quot; media-type=&quot;text/xml&quot;/>

1. Using XSLT, how do I prevent "empty" elements (elements not having data and not elements with EMPTY declaration) from converting to XML empty syntax?

INPUT:

<entry></entry>

OUTPUT:

<entry/>

DESIRED OUTPUT:

<entry></entry>

2. XSLT converts ' and

"

. Is there a way for XSLT not to convert these two entities. XSLT retains

< >

and

&

.

INPUT:

< > & and" stages'

OUTPUT:

< > & and" stages'

DESIRED OUTPUT:

< > & and" stages'

3. I need to preserved certain markups in my XML file. For example, all data within <myTag>. <xsl:copy-of> is not working. How do I do it in XSLT?

INPUT:

<p>data data &hellip;<myTag>&auml;</myTag>&hellip; data data.</p>

OUTPUT:

<p>data data ...<myTag>ä</myTag>... data data.</p>

DESIRED OUTPUT:

<p>data data ...<myTag>&auml;</myTag>... data data.<p>

Thanks for all the help!

 

[Wiszh]

If you use the Saxon xslt transformer (for Java) it will leave any empty elements.

As far as keeping your markup try using a <xsl:text> tag

 

[johnrbradley]

Just do this;
<xsl:text disable-output-escaping=&quot;yes&quot;>
BLAH BLAH BLAH
</xsl:text>
If I misunderstand your quesiton due to the ridiculous processing of entities in [ code ] and [ /code ] segments, please correct me.


Regards,
John