XSLT just sort the XML 1

[jstreich]

I have a atom file file that looks like

<?xml version="1.0" encoding="utf-8"?>
<feed xmlns="[URL unfurl="true"]http://www.w3.org/2005/Atom">[/URL]
  <title>Zimbra CIE_Events</title>
  <generator>Zimbra Atom Feed Servlet</generator>
  <updated>2009-04-16T15:41:55-05:00</updated>
  <entry>
    <title>Culture Cafe </title>
    <updated>2009-04-23T14:00:00-05:00</updated>
    <summary/>
    <author>
      <name/>
      <email>foo@uwm.edu</email>
    </author>
  </entry>
...
</feed>

I want/need it in the same format, but I need it sorted.

I tried:

<xsl:stylesheet xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform"[/URL] version="1.0">

  <xsl:output method="xml"/>

  <xsl:template match="/feed/entry">
    <xsl:apply-templates>
      <xsl:sort select="updated"/>
    </xsl:apply-templates>
  </xsl:template>

</xsl:stylesheet>

The result isn't pretty, but it's not terribly far from what I want. What I get back is:

Zimbra CIE_EventsZimbra Atom Feed Servlet[URL unfurl="true"]http://login01.pantherlink.uwm.edu/service/home/pooney/CIE_Events.atom2009-04-16T15:59:46-05:00Culture[/URL] Cafe 2009-04-23T14:00:00-05:00foo@uwm.edu...

I've not toched XSLT in a long time, and I'm looking for a fast and cheap solution.

 

[tsuji]

[tt]<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="[ignore]

http://www.w3.org/1999/XSL/Transform

[/ignore]"
xmlns="[ignore]

http://www.w3.org/2005/Atom

[/ignore]"
xmlns:atom="[ignore]

http://www.w3.org/2005/Atom

[/ignore]"
>
<xslutput method="xml" version="1.0" encoding="utf-8" indent="yes" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="*|@*|comment()|processing-instruction()|text()">
<xsl:copy>
<xsl:apply-templates select="*|@*|comment()|processing-instruction()|text()" />
</xsl:copy>
</xsl:template>
<xsl:template match="atom:feed">
<xsl:copy>
<xsl:apply-templates>
<xsl:sort select="atom:updated" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>[/tt]

 

[jstreich]

Thanks, that gets me valid xml, but the sort doesn't appear to work; what I get out is no different than what went in.

 

[tsuji]

It should sort (?) to my understanding. If the original feed is already in some order, it could result in the same output. Try ascending and then descending setting for order attribute, in that case it should show up different result for sure one way or another.
[tt] <xsl:sort select="atom:updated" order="ascending" /> <!-- or "descending" -->
[/tt]

 

[tsuji]

I have just checked against a randomly chosen atom feed out-there:
ref

http://fdsys.blogspot.com/atom.xml

Their entries are in the order of "descending". If I use the xsl as I posted, supplemented with additional namespaces proper to that feed, I can obtain output reversing the order.
[tt]
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="[ignore]

http://www.w3.org/1999/XSL/Transform

[/ignore]"
xmlnspenSearch="[ignore]

http://a9.com/-/spec/opensearch/1.1/

[/ignore]"
xmlns:georss="[ignore]

http://www.georss.org/georss

[/ignore]"
xmlns:gd="[ignore]

http://schemas.google.com/g/2005

[/ignore]"
xmlns="[ignore]

http://www.w3.org/2005/Atom

[/ignore]"
xmlns:atom="[ignore]

http://www.w3.org/2005/Atom

[/ignore]"
>
<xslutput method="xml" version="1.0" encoding="utf-8" indent="yes" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="*|@*|comment()|processing-instruction()|text()">
<xsl:copy>
<xsl:apply-templates select="*|@*|comment()|processing-instruction()|text()" />
</xsl:copy>
</xsl:template>
<xsl:template match="atom:feed">
<xsl:copy>
<xsl:apply-templates>
<xsl:sort select="atom:updated" order="ascending" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>[/tt]

 

[jstreich]

Order indeed worked! Thanks.

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