XML with XSLT

[benoxy]

I would like to make a tansformation of an XML file to another XML with XSLT.
My example don't work why ?
=xmllib->XSLT( "<RAE><vmaj>0</vmaj><vmin>0</vmin></RAE>","<?xml version=""1.0"" encoding=""UTF-8""?>"
+"<xsl:stylesheet xmlns:xsl=""

http://www.w3.org/1999/XSL/Transform""

version=""1.0"">"
+"<xsl:template match='node()'><xsl:copy> <xsl:apply-templates select=""node()|@*""/> </xsl:copy></xsl:template>"
)
Thank

 

[janhes]

Is this a map problem or an xslt problem?
If a map can you give more details - version, patch level error message etc.

 

[benoxy]

The problem is the code xslt. I use an parameter the xsl text fragment.The WTX is version 8.1. No error in the log. The generated XML file is empty and contains no tag.

 

[janhes]

Have you got service pack 3 installed?

 

[janhes]

The XSLT function has 2 parameters
XSLT ( xml_url_or_xml_fragment, xslt_url_or_xslt_fragment )

The example in the manual shows

xmllib->XSLT( ?ipo.in.xml?, ?ipo.xsl? )
or
xmllib->XSLT( PACKAGE( source ), ?ipo.xsl? )

 

[benoxy]

I've pack 3. If I understand it is necessary to file a xsl and not code xsl in the second parameter xmllib->XSLT(param1,param2).

 

[janhes]

Have you tested that your xsl works on that xml outside WTX?

 

[benoxy]

Yes, I tested it with my oXygen and processing is done.