Nov 16, 2008 #1 Jawhar520 Programmer Nov 16, 2008 2 CN Does anyone know why int 19h routine load the boot loader to 7c00h?is there any cause?
Nov 17, 2008 #2 Salem Programmer Apr 29, 2003 2,455 GB Think back to the early 1980's, when 64K was the least memory you could guarantee would exist on a PC. http://en.wikipedia.org/wiki/IBM_PC That's probably why it's within the first 64K of the address space. If you dig around in the original architecture, you'll probably find a more specific reason. -- If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut. Upvote 0 Downvote
Think back to the early 1980's, when 64K was the least memory you could guarantee would exist on a PC. http://en.wikipedia.org/wiki/IBM_PC That's probably why it's within the first 64K of the address space. If you dig around in the original architecture, you'll probably find a more specific reason. -- If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
Nov 17, 2008 Thread starter #3 Jawhar520 Programmer Nov 16, 2008 2 CN thank you Salem. Upvote 0 Downvote