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what is wrong with this code?

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rachelason

rachelason

Programmer
Jun 28, 2004
114
GB
Hello everyone!,

Though i am new to xml and xslt , i have managed to create an xml file. But when i try to display the information using xsl, it displays only one row of the data. As you can see from the xsl code, i have added <for-each tag aswell. I am not sure what the <xsl:template match >code does and i wonder if that's causing the problem. I have nearly 1000 rows in the xml, but it doesn't display if used with the following xsl. Any help?

Here is the code.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="<xsl:template match="/">
<html>
<body>
<h2>Tape Profile - File List</h2>
<table border="1">
<tr bgcolor="#006699">
<th align="left">FileName</th>
<th align="left">Fragment</th>

</tr>
<xsl:for-each select="profile">
<tr>
<td><xsl:value-of select="filename"/></td>
<td><xsl:value-of select="fragment"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>

</xsl:stylesheet>

thanks
Rachel
 
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And this is the content of the xml file

<?xml version="1.0" encoding="utf-8" ?>
<?xml-stylesheet type="text/xsl" href="c:/xslfile.xsl"?>
- <profile>
<filename>0182F5E0</filename>
<fragment>0</fragment>
<filename>0182F6B0</filename>
<fragment>0</fragment>
.......
</profile>

Also, how important it is to have xml schema in the xml file? If it's an application(not internet related site), do i still have to have a schema to define the taglist.

Thanks
 
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The corresponding lines.
[1]
[tt]<xsl:template match="profile">[/tt]
[2]
[tt] <xsl:for-each select="child::*[position() mod 2 = 1]">
<tr>
<td><xsl:value-of select="."/></td>
<td><xsl:value-of select="following-sibling::*[1]"/></td>
</tr>
</xsl:for-each>
[/tt]
 
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I have managed to solve the problem,,, obviously the xml file didn't have a tag to seperate each block of code
<filename><fragment> should be inside a another tag.
thanks
 
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>obviously the xml file didn't have a tag to seperate each block of code <filename><fragment> should be inside a another tag
You know, that is incorrect. You do what you like but the statement is wrong.
 
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here is my code.... it seemed to work this way. Since i am new to xml, i tend to believe that that's how it has to be done. Sorry i don't under your first reply though.


<?xml version="1.0" encoding="utf-8" ?>
<?xml-stylesheet type="text/xsl" href="c:/xslfile.xsl"?>
<tape>
- <profile>

<filename>0182F5E0</filename>
<fragment>0</fragment>
<filename>0182F6B0</filename>
<fragment>0</fragment>
.......
</profile>
</tape>


xsl file

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="<xsl:template match="/">
<html>
<body>
<h2>Tape Profile - File List</h2>
<table border="1">
<tr bgcolor="#006699">
<th align="left">FileName</th>
<th align="left">Fragment</th>

</tr>
<xsl:for-each select="/tape/profile">
<tr>
<td><xsl:value-of select="filename"/></td>
<td><xsl:value-of select="fragment"/></td>

</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>

</xsl:stylesheet>
 
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>Sorry i don't under your first reply though.
You are question poster, you should change document to the form you understand. No reason to work with anything you don't understand.
 
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I meant to write 'understand'
And i meant i don't understand the code you posted in reply to my question.
Anyway, the problem i had was solved. So don't worry.
 
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rachelason,

In your penultimate post, your stylesheet does not match your XML document. tsuji posted a solution which will work with the XML document as posted both times. Since you don't understand the code, both he and I can explain it, line by line. "If you teach a man to fish..."

Here is the code tsuji is suggesting, with my comments added:
Code: 
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform">[/URL]
<xsl:template match="/">
  <html>
  <body>
    <h2>Tape Profile - File List</h2>
    <table border="1">
    <tr bgcolor="#006699">
      <th align="left">FileName</th>
      <th align="left">Fragment</th>
     
    </tr>
    [COLOR=blue]<!-- apply templates to the children of the root node
         which in this case means the profile element -->[/color]
    <xsl:apply-templates/>
    </table>
  </body>
  </html>
</xsl:template>
<xsl:template match="profile">
    [COLOR=blue]<!-- for each odd numbered (by document order position) 
         child element of the profile element -->[/color]
    <xsl:for-each select="child::*[position() mod 2 = 1]">
    [COLOR=blue]<!-- I think child::*[local-name() = 'filename']
         would work equally well -->[/color]
     <tr>
      [COLOR=blue]<!-- output the value of the filename element -->[/color]
      <td><xsl:value-of select="."/></td>
      [COLOR=blue]<!-- output the value of the immediately 
         following sibling (in document order) which is the
         fragment element -->[/color]
      <td><xsl:value-of select="following-sibling::*[1]"/></td>
     </tr>
    </xsl:for-each>
</xsl:template
</xsl:stylesheet>

I hope you find this solution to the problem you iriginally posted useful and informative.

Tom Morrison
 
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