$variables question

[mettodog]

this is what i want to do:

$str_box_body = "require ('common/login.php')"

of course, this produces a parse error.

How can i make this work?

 

[Hokey]

I just made a file test.php with the following:

<?
$str_box_body = &quot;require ('common/login.php')&quot;;
echo $str_box_body;
?>

and it did output: require ('common/login.php')

Are you tring to just assin the string &quot;require ('common/login.php')&quot; to the variable $str_box_body? If so then that should work. The only possible thing I could see wrong with your example above is a missing semi-colan at the end.

 

[mettodog]

no, i dont want to assign it as a string, i want php to actually parse that line of code.

 

[rycamor]

$str_box_body = "require(\"common/login.php\");";

eval($str_box_body);

eval() is a command that evaluates an expression or variable *as* PHP code and then runs the results.

 

[Hokey]

In that case you could just put in:
require (&quot;common/login.php&quot;

If that line of code is included conditionaly then I would use the include() command:
if (conditional statemen) include (&quot;common/login.php&quot;

I have never used the eval() command, but I could see where it would be handy if you had the same file included/required several times through out a application.