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Variables doesn't works

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egmweb

egmweb

Programmer
Mar 19, 2004
147
EU
Hello all.

I'm making a website based on php/mysql and I have some functions which I include in index.php at begin of this file.

But I have a problem with the variables... when I send a variable through get method to the next .php page, it displaay the following errors:

Notice: Undefined variable: error in C:\Apache2\htdocs\pcplus\index.php on line 257

thanks you.
 
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hi, No sorry, but i'm not understanding what've you said in this code....

I have a Index.php and it has html.

I have different static links in the category menu:

Tools > link: index.php?catid=2
Misc > link: index.php?catid=3 etc.... in the first index.php I have no form to send this variables... justo click on the link and I'm sending the variable through url.

But I think that the code is fine, because it was working good before.... Some guy edit the php.ini and the website doesn't works...

Thanks you
 
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I forgot to tell you that The Version of PHP is 4.3.4
 
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The values submitted in the URL have to be going somewhere. The most likely place is $_GET.

If you create a PHP script called show_get.php, which reads:

Code: 
<?php
print '<html><body><pre>';
print_r ($_GET);
print '</pre></body></html>';
?>

And you point your browser to [ignore][/ignore], what is output to the browser?



Want the best answers? Ask the best questions!

TANSTAAFL!!
 
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Sorry it took me so long to come back to the thread.
DrJ said:
...This actually is not a Warning, it is merely a notice...
My mistake, just a Notice.

but still Checking the setting for the directive i mentioned is not a bad idea. I agree with Sleipnir on checking what is actually contained in the $_GET superglobal.

Also, you asign $error the value of $_GET['error'] at the beggining of the script, but where do you use it.

I gonna take a stab in the dark here:
If you use it inside a function somewhere it has to be passed into the function for example if you do this:

Code: 
$error=$_GET['error'];

And then have function that uses it like so:

function check_error(){
if($error=='somevalue'){
do something
}
}

This will generate a notice since [red]$error[/red] is not defined in the function's scope. You have to pass to the function or define it as a global variable.



----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.
Click to expand...
Click to expand...
 
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I really wish there were an option to edit ones post any way, what i forgot to say is:

You told us you get this error:
egarcia said:
Notice: Undefined variable: error in C:\Apache2\htdocs\pcplus\index.php on line 257
Click to expand...
Can you tell us what is in line 257 of your code.

----------------------------------
Ignorance is not necessarily Bliss, case in point:
Unknown has caused an Unknown Error on Unknown and must be shutdown to prevent damage to Unknown.
 
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