Variable Substitution - floating point numbers 1

[ooids]

Hi!

I have a very basic script:
#!/bin/ksh

A=0.5
B=0.5

C=$((A * B))
echo $C

It returns 0 - How do i get it to output to 2dp / control the precision of the variables?

Many Thanks

 

[vgersh99]

use 'bc' for floating point arithmetics vlad
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[dchoulette]

Yes, I suggest you use 'bc'.
... or 'dc' if you like more exotic RPN syntax.

 

[ooids]

Thanks..

Would either of you be able to give me an example of using bc on my script? I'm a newbie, not used bc before..

 

[dchoulette]

C=$(echo "$A + $B" | bc);

 

[vgersh99]

You might consider a finer precision for the floating point arirthmetics - say FOUR decimal points:

C=$(echo &quot;scale=4;${A} + ${B}&quot; | bc); vlad
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|#include<disclaimer.h> |
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[ooids]

Thanks a lot for the help - just what i need...