Variable in Get URL!!!!

[willbo]

im trying to place something like this:
(random (100))+1 add ".jpg"
So i can load a random .jpg file into a blank window from a group of a hundred .jpg's when a button is pressed... but i CANT seem to get the symantecs right cause it just dont take!
HELP!

 

[davdesign]

REPEAT OF PREVIOUS POST!!

if your not bothered about formatting, ie: just having a jpg load into a new window, top-left justified, you could just use the following:


image = random(100)+1;
getURL ("

http://www.yourdomainname/"+image+".jpg",

"_blank"


dave

dave@pinkzeppelin.com

^^^^^^^^^^^^^^^^^^^^^​

 

[willbo]

Ok well im real sorry for being some kind of idiot newbie, but i copied and pasted your code and tryed some different variations on it trying to even get a NUMBER instead of the +image in the URL, but to no avail. i get a 404 everytime.

The requested URL /("

http://www.peekaboosystems.com/";+image+".jpg",

"_blank" was not found on this server.

since im an idiot i dont know if a semicolor or quote is off, or if i need to var image first on the button press... god sorry. Ill try to figure it out

 

[willbo]

well i got the button working just by doing
(random (3))+1 add ".jpg"
with the .jpg's in the root. this will work. who knows where i went wrong in the other statement.

 

[davdesign]

willbo

If you were typing in the semi-colon after the URL, then that was my mistake for not 'TGML coding' my actions. Apologies.

dave

dave@pinkzeppelin.com

^^^^^^^^^^^^^^^^^^^^^​

 

[willbo]

NO PROB MAN!!