variable in awk....

[nymus]

Hi,

In a script I take the variable NF and print it:

BEGIN {FS=": "}
...
$1 ~ /first mount/ {print $NF}
...

result:
Tue Jul 23 14:26:37 DFT 2002

Now I want to put the last field of $NF (2002) in a variable:

$1 ~ /first mount/ {First="$NF|print $NF";print First}

But I don't see how? Has anyone an idea?
B.regards
nm

 

[p5wizard]

look at split function in your awk man page


HTH,

p5wizard

 

[Mag0007]

Try this:

d="Tue Jul 23 14:26:37 DFT 2002"
ans=array[split(d,array)]
print ans

is this what you want?

 

[nymus]

I've used split like so:

$1 ~ /first mount/ {split($NF,FMount," ")}
...
print "Fist Mount :"FMount[6]

it's work well....

Thanks a lot for your help