Variable Declaration ..

[fravio]

Hi,

If we are declaring a variable inside a loop, what will happen to the instance of that variable before the next iteration? Does it mean that each time the variable is created though its not being explicitly destroyed at the end of each iteration...Case is same for local function variables also..This may sound funny...but i just want to know how it is...

Fravio..

 

[2ffat]

for (i=0; i<10; ++i)
{
   // i's scope exists until the loop ends
   int x = 0; // x's scope exists until the loop ends

   // however, x is intialized every iteration of loop
}
// can't see i or x

James P. Cottingham

I am the Unknown lead by the Unknowing.
I have done so much with so little
for so long that they think I am now
qualified to do anything with nothing.

 

[Zyrenthian]

In the loop above, x will be re-initialized to zero every time.

Matt

 

[Zyrenthian]

Ya know, I am so bad at reading comments

LOL
Matt

 

[keepItSimple]

in the for loop above:

for (i=0; i<10; ++i) I assume that i is declared above the for loop, so i will still be in scope after the loop ends

Ricky



Failure is not falling down, it's staying down.

 

[Zyrenthian]

You would like to assume that and by design that is how it is SUPPOSED to be. However,


for(int i = 0;i<7;i++)
{
}

for(int i = 0;i<10;i++)
{
}

Will produce multiple definition errors. If you instead do

{
for(int i = 0;i<7;i++)
{
}
}

{
for(int i = 0;i<10;i++)
{
}
}


there will be no issues

Matt

 

[fravio]

Thanx guys..its become more clear now..