Using Pattern to find entities

[DrHyper]

[ignore]How do I modify the code (or the reg. expression) below, so that I get :
groupStr0 = "
groupStr1 = &
groupStr2 = '
groupStr3 = <

instead of only:
groupStr0 = "

*************************************************'

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PatternTest {
public static void main(String[] args) {
String testData = "" tada dum di & dum ' dum; < dum dum tada";
Pattern p = Pattern.compile("(&\\w+");
Matcher matcher = p.matcher(testData);
boolean matchFound = matcher.find();

if (matchFound) {
// Get all groups for this match
for (int i = 0; i < matcher.groupCount(); i++) {
String groupStr = matcher.group(i);
System.out.println("groupStr" + i + " = " + groupStr);
}
}
}
}
[/ignore]

 

[DrHyper]

...well my entities are obv. shown as ",&,' and <

..new example:
How do I modify the code (or the reg. expression) below, so that I get :
groupStr0 = &a;
groupStr1 = &bb;
groupStr2 = &ccc;
groupStr3 = &dddd;

instead of only:
groupStr0 = &a;
*****************************

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PatternTest2 {
public static void main(String[] args) {
String testData = "&a; tada dum di &bb; dum &ccc; dum; &dddd; dum dum tada";
Pattern p = Pattern.compile("(&\\w+");
Matcher matcher = p.matcher(testData);
boolean matchFound = matcher.find();

if (matchFound) {
// Get all groups for this match
for (int i = 0; i < matcher.groupCount(); i++) {
String groupStr = matcher.group(i);
System.out.println("groupStr" + i + " = " + groupStr);
}
}
}
}

 

[DrHyper]

doh! found the solution:

int i = 0;

while (matcher.find()) {
System.out.println("groupstr" + i + " = " + matcher.group());
i++;
}