BlueDragon2, TLady and Geoff, many thanks for your replies and your time. This note is just to summarise both the problem and to my progress with it since the original posting: I think it's now solved.
BlueDragon2 - I actually want to be able to select the Nth ordered entry from the list, ignoring duplicates, and to copy that entry into a cell of my choosing. I originally assumed this would be an easy task, because if I apply a filter to the original list (using the Filter item on the Data menu), the resulting drop-down menu supplies me with exactly the list of choices I want, from which all I'd have to do is pick the 1st, 2nd, 3rd item or whatever. I wasn't however able to find a built-in function that would perform that task.
TLady - my apologies for not making the problem clearer. You are right in saying that I effectively want to loop through every cell and read those values that are different from values already read - except that I want to select the Nth ordered item from that list.
Geoff - many thanks for your GetUnique function: it looks like exactly what I'm after, given that there doesn't appear to be a built-in function to do what I want.
I've been experimenting since placing the original query, and have discovered that setting up a pivot table (on the Data menu) comes very close to what I need, since the row or column headings of that table can be made to contain the list I want. The only problem with it is that I'd like the list I produce to update automatically each time I change the original list - and pivot tables don't automatically update when the original list is changed.
I've also been looking for anything previously posted on Tek-Tips, and found a reference to a website which discusses duplicate and unique items in lists (
Under "Extracting Unique Entries" is made the same point as in the previous paragraph about automatic updating, together with an array formula which apparently cracks the problem - so I think my problem might also be solvable this way. I'm now going to do some experimenting...
Again, thank you all for your time and efforts.
Best regards,
DQR