Trying to figure out how to figure this out.
128,64,32,16 =240
256-240=16
This leaves a 48-64 span. 49 1st host, 62 last. 63 broadcast addr.
Is this right
Meaning the answer would be "c"
Which IP address range is allowable given an IP address of 172.37.2.56 and 12-bit subnetting?
a. 172.37.2.48 to 172.37.2.63
b. 172.37.2.48 to 172.37.2.62
c. 172.37.2.49 to 172.37.2.62
d. 172.37.2.55 to 172.37.2.126
128,64,32,16 =240
256-240=16
This leaves a 48-64 span. 49 1st host, 62 last. 63 broadcast addr.
Is this right
Meaning the answer would be "c"
Which IP address range is allowable given an IP address of 172.37.2.56 and 12-bit subnetting?
a. 172.37.2.48 to 172.37.2.63
b. 172.37.2.48 to 172.37.2.62
c. 172.37.2.49 to 172.37.2.62
d. 172.37.2.55 to 172.37.2.126