trouble when transforming xml with xsl

anarian · Feb 27, 2005

Hello there!

I'm trying to transform a xml using an xsl but nothing is printed out.
I guess that there is something wrong with the namespace but i really don't know what should i do to fix it.

So here is the xml and the xsl also:

<?xml version="1.0" encoding="UTF-8"?>
<library xmlns="

http://www.thalis.org"

xmlns:dc="

http://purl.org/dc/elements/1.1/"

xmlns:dcterms="

http://purl.org/dc/terms/"

xmlns:xsi="

http://www.w3.org/2001/XMLSchema-instance"

xsi:schemaLocation="

http://www.thalis.org

d.xsd">
<course ID="1">
<dc:title>ir</dc:title>
<dc:creator>mplampla</dc:creator>
<dcterms:educationLevel>pr</dcterms:educationLevel>
<dc:description>sfsfsaf</dc:description>
<dcterms:tableOfContents>dfsf</dcterms:tableOfContents>
<dcterms:created>2004-12-21</dcterms:created>
<dcterms:modified>2005-01-21</dcterms:modified>
<dc:subject>dads</dc:subject>
<dc

ublisher>dada</dc

ublisher>
<dc:identifier>wdasdad</dc:identifier>
</course>
<course ID="2">
<dc:title>dwdm</dc:title>
<dc:creator>maria</dc:creator>
<dcterms:educationLevel>pr</dcterms:educationLevel>
<dc:description>sfsfsaf</dc:description>
<dcterms:tableOfContents>dfsf</dcterms:tableOfContents>
<dcterms:created>2004-12-21</dcterms:created>
<dcterms:modified>2005-01-21</dcterms:modified>
<dc:subject>dads</dc:subject>
<dc

ublisher>dada</dc

ublisher>
<dc:identifier>wdasdad</dc:identifier>
</course>
</library>

and the xsl is

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns="

http://www.thalis.org/"

xmlns:xsl="

http://www.w3.org/1999/XSL/Transform"

xmlns:dc="

http://purl.org/dc/elements/1.1/"

xmlns:dcterms="

http://purl.org/dc/terms/">

<xsl

utput method="html" indent="no"/>
<xsl:template match="/">

<html>
<head>
<title>Thalis</title>
</head>
<body>

<table border="2" align="center">
<xsl:for-each select="library/course">
<tr>
<td>
<a target="_blank" href="details.php?cid={@ID}">
<xsl:value-of select="//dc:title"/>
</a>
</td>
<td><xsl:value-of select="//dc:creator"/></td>
<td><xsl:value-of select="//dcterms:educationLevel"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

If anyone could help it would be much appreciated.
Maria

JontyMC · Feb 28, 2005

When you have a default namespace, to transform it you must use a namespace prefix even though it is the default in the XML doc. See this for more info:

http://www.tek-tips.com/faqs.cfm?fid=1188

So your XSL header should be:

Code:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:myprefix="[URL unfurl="true"]http://www.thalis.org/"[/URL] 
xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform"[/URL] 
xmlns:dc="[URL unfurl="true"]http://purl.org/dc/elements/1.1/"[/URL]
xmlns:dcterms="[URL unfurl="true"]http://purl.org/dc/terms/">[/URL]

Then specify your nodes:

Code:

<xsl:for-each select="myprefix:library/myprefix:course">

anarian · Feb 28, 2005

A lot of thanxs!!!
Now it's work really fine

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trouble when transforming xml with xsl

anarian

Programmer

JontyMC

Programmer

anarian

Programmer

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