Tough Question... sub nodes, multiple match...

[rjonesX]

Here is how the XML is set out...

{?xml version="1.0" ?}
{?xml:stylesheet type="text/xsl" href="main.xsl" ?}
{ussa}
{update}
{field id="TITLE" taborder="1"}
{field_value}Jenny{/field_value}
{/field}
{field id="TYPE" taborder="2"}
{field_value}LEGISLATIVE UPDATE FACT SHEET{/field_value}
{/field}
{field id="BLURB" taborder="3"}
{field_value}110 Crown Drive{/field_value}
{/field}
{field id="DATE" taborder="4"}
{field_value}Oklahoma City, OK 73114{/field_value}
{/field}
{field id="ORDER" taborder="5"}
{field_value}4055559873{/field_value}
{/field}
{field id="STATUS" taborder="6"}
{field_value}CURRENT{/field_value}
{/field}
{/update}
{/ussa}

basically, here is what Im doing:

I am calling an xsl:for-each where the field_value of field id "STATUS" is equal to "CURRENT"

Other entries can have CURRENT or ARCHIVED as their value (to divide articles by current or archived... pretty simple)

First, I need to know how to do that.. here is what I guessed...

{xsl:for-each select="ussa/update[field/field_value$eq$'CURRENT']"}

is this correct? is there anyway I can get it to include the attribute? @ID=STATUS in there so it knows what node to check?

also, how can I havae it after that use the {xsl:if} command to further separate the xml by only printing out those who are marked current and have the @id=type value of LEGISLATIVE UPDATE FACT SHEET ???

any ideas???

russ jones
rjones@email.unc.edu

 

[ixian]

russ,

use xsd functions(that will seperate the current and archieved listing----plus what ever other type of data schemas that you wish to have broken down) that then tie into to your xsl.

Aaron Fear is the mind killer!!!!!!