to get pwd value 1

[hendnov]

Hi guys,

Here's part of my code which called summary.ksh :

if [$1 == "\."]
then 
input = pwd
echo "input =" $input
fi

I want to have the full path directory if the input is "."
so

if I'm at the directory /opt/adoc
when I execute the script, I want the $input = /path/of/directory, the result would be something like this :

/opt/adoc> summary.ksh .
input = /opt/adoc

Could you guys help me ?

 

[PHV]

Why not simply this ?
input=$(cd "$1" && pwd -P)
echo "input = " $input

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[p5wizard]

like this (for ksh)?

echo "dir? (use '.' for current dir)"
read input
if [ ${input} = '.' ]
then
input=$(pwd)
echo "input = " ${input}
fi


HTH,

p5wizard

 

[Ogzilal]

Hi,

Shell in an interpreted language, not a compiled one.
So avoid all spaces around tokens.

input=$(pwd)
echo "input =" $input

for working directory purpose, you can use the predefined shell variable $PWD

 

[hendnov]

THX GUYS,