string replace doesn' work with double quote qualifier 1

[jmoeller18]

using the string replace function and change any new lines into html breaks

and $fb=str_replace('\n', &quot;<br><br>&quot;, $fb);

this works - single quote qualifier

'Success\n\n'

this doesn't - double quote qualifier

&quot;Success\n\n&quot;

Why?


Jeffrey E. Moeller

http://www.JeffreyMoeller.com

 

[sleipnir214]

[In my answer, I'm going to be very explicit with my use of single- and double-quotes.]


Your problem is because of PHP's string-interpolation rules.

In PHP, &quot;\n&quot; and '\n' are not the same thing.

&quot;\n&quot; is the single newline character, because escaped characters are interpolated inside double-quoted string literals in PHP.

'\n' is the literal string &quot;<backslash>n&quot; (two characters), because escaped characters are not interpolated inside single quotes in PHP.

In your invocation of str_replace(), you use '\n' as your &quot;search-for&quot; string, so you're telling PHP to look for &quot;<backslash>n&quot; in the string &quot;Success<newline><newline>&quot;.

'<backslash>n' does not appear in &quot;Success<newline><newline>&quot;. '<backslash>n<backslash>n', however, does appear twice in 'Success<backslash>n<backslash>n'.



I would also like to draw your attention to the special-purpose PHP builtin function, nl2br() (

http://us4.php.net/manual/en/function.nl2br.php).

It's designed to do what you're doing right now.


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[jmoeller18]

very excellent, that moves my understanding forward
i was looking for a precise definition of &quot;interpolation&quot; in regards to PHP when I stumbled upon this article that built upon for me what you had presented

http://www.devarticles.com/c/a/PHP/Some-PHP-Guidelines-to-Live-By/1/

Jeffrey E. Moeller

http://www.JeffreyMoeller.com