Spaces interpreted as newline 1

[630111]

Here's my script

#! /bin/sh
SPAN1="-d 10/18/2004 17:00 -e 10/22/2004 06:00"
SPAN2="-d 10/22/2004 17:00 -e 10/25/2004 06:00"
SPAN3="-d 10/25/2004 17:00 -e 10/29/2004 06:00"

for I in $SPAN1 $SPAN2 $SPAN3
do
echo $I
done

My output looks like this

-d
10/18/2004
17:00
-e
10/22/2004
06:00
-d
10/22/2004
17:00
-e
10/25/2004
06:00

How do I get it to output like this?

-d 10/18/2004 17:00 -e 10/22/2004 06:00
-d 10/22/2004 17:00 -e 10/25/2004 06:00
-d 10/25/2004 17:00 -e 10/29/2004 06:00

Thanks, in advance!
630111

 

[PHV]

What about this ?
for I in "$SPAN1" "$SPAN2" "$SPAN3"
do
echo "$I"
done


Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[vgersh99]

for I in "$SPAN1" "$SPAN2" "$SPAN3"

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[630111]

THANKS PHV !!

Why are the quotes necessary around the variables?

Much appreciated
630111

 

[PHV]

In your shell man page take a look at 'shell quoting mechanism', 'variable substitution', 'IFS', 'for .. in', ...

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244