six "syntax error" messages

[Cornelius19]

Hi,

I need to run an awk script written by someone else seven years ago and probably working fine in that configuration. Now I receive six "syntax error" messages (no other errors), the first two are:

awk: iprjen.awk:72: aFtagHierarchy[$1][
awk: iprjen.awk:72: ^ syntax error
awk: iprjen.awk:275: is_not_baseform = aFtagHierarchy[bfpos][featag]
awk: iprjen.awk:275: ^ syntax error

Here are the corresponding lines in the awk file:

lines 71-73 (in the BEGIN section):

      else {
         aFtagHierarchy[$1][$2] = $3;
      }

lines 273-278 (in a user defined function):

   	else 
   	{
   		is_not_baseform = aFtagHierarchy[bfpos][featag]
			if ( is_not_baseform == "" )
				is_not_baseform = "9";
		}

Do you have any idea what is wrong? I use gawk 3.1.5 (under cygwin).

Thanks,

Cornelius

 

[feherke]

Hi

Hmm... Sure it is [tt]gawk[/tt], the GNU implementation of [tt]awk[/tt] ? As far as I know, that was never valid code. In multiple dimensioned arrays use comma ( , ) to separate indexes written between a single pair of brackets ( [] ) :

      else {
         aFtagHierarchy[$1[red],[/red]$2] = $3;
      }

Feherke.

http://rootshell.be/~feherke/

 

[Cornelius19]

Thanks a lot for the suggestion: I used coma and single pair of brackets instead of the double pair of brackets and the two error messages disappeared.

I still get some errors however, here are the next two (the fifth and sixths are the same as the third):

awk: iprjen.awk:306:                substr(aPrintArray[1], 8, 1) = "0";
awk: iprjen.awk:306:                                             ^ syntax error
awk: iprjen.awk:307:             else {
awk: iprjen.awk:307:             ^ syntax error

Lines 305-307 are:

            if ( inflform == baseform )
               substr(aPrintArray[1], 8, 1) = "0";
            else {

Would you have some suggestion for these as well?

Thanks,

Cornelius

P.-S. The company who developed this code was sold to a second company and we bought that second company and we do not have much documentation. So, at this point, it is not clear which version of awk they were using.

 

[feherke]

Hi

Another thing that barely could work in any [tt]awk[/tt] :

substr(aPrintArray[1], 8, 1) =[red]=[/red] "0";

Feherke.

http://rootshell.be/~feherke/

 

[Cornelius19]

Thanks a lot again. All the syntax error messages disappeared but a new one appeared instead:

awk: iprjen.awk:117: (FILENAME=iprjen.uni FNR=1) fatal: attempt to use scalar `a
PrintArray' as array

Here are lines 112-117:

      # if we have a print array, process it first
      if ( length(aPrintArray) > 0 ) {
         fnProcessParadigm();
      }
      # clean up: set counters back to zero
      delete aPrintArray;

I am wondering why it is considered a scalar. Curiously, it is not a problem in 113 but it is in 117.

Any suggestion?

Cornelius

 

[feherke]

Hi

You try to use both the [tt]length()[/tt] and [tt]delete[/tt] functions on the same variable. As [tt]length()[/tt] expects a scalar value and [tt]delete[/tt] expects an array element ( or array in [tt]gawk[/tt] ), one of them must fail.

As in standard [tt]awk[/tt] ( and neither in [tt]gawk[/tt] ) there is no function to get the size of an array ( Ok, [tt]asort()[/tt] returns the size, but you pay for it with the speed ), I suggest to add your own function and use it instead :

      # if we have a print array, process it first
      if ( [red]a[/red]length(aPrintArray) > 0 ) {
         fnProcessParadigm();
      }
      # clean up: set counters back to zero
      delete aPrintArray;



[gray]# ...[/gray]



[gray]# Calculates an array's size[/gray]
[gray]#   a - array which size to be calculated[/gray]
[gray]#   returns - the size of the array[/gray]
[b]function[/b] alength(a)
{
  n=0
  [b]for[/b] (i [b]in[/b] a) n++
  [b]return[/b] n
}

Feherke.

http://rootshell.be/~feherke/

 

[PHV]

For your error posted 4 Jun 07 14:44, replace this:
substr(aPrintArray[1], 8, 1) = "0"
with this:
aPrintArray[1]=substr(aPrintArray[1],1,7)"0"substr(aPrintArray[1],9)

I wonder which version of awk was supposed to admit such syntax ...

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[feherke]

Hi

Ah, indeed, was not a test condition. Thanks, PHV.

Feherke.

http://rootshell.be/~feherke/

 

[Cornelius19]

Thanks a lot – it is really great to be able to get help from knowledgeable people like you! I applied PHV’s modification and feherke’s function (and a couple of other easy changes). Now I can run the script, get an output file and the result looks good.

Cornelius

P.-S. I consider posting the script (or at least some problematic parts of it) in a new thread so that someone could identify the version of awk it would run on.