silly question

[zag]

silly question i know, but how do i use printf to print:
999,999,999
instead of
999999999?
i thought there was a format specifier for it!

 

[maschwa]

If you mean the string "999,999,999" it´s very easy:

puts("999,999,999"

;-)

br maschwa

 

[jtm111]

Nope, there is not a simple function to do this. You have to look around for someone else's code. I'd bet there's a lot of code out there, I have some C++ code that does currency. But your request is not a simple request.

 

[zag]

Thanks for your responses, guys - i figured maybe i'd forgotten a specifier, however to make myself a bit clearer, maschwa i don't actually know what the output is going to be... sorry, i should have said 999,999,999 was just an example of some numeric output - i didn't want to re-invent the wheel if there was a way of putting the commas in the right place automatically.

jtm111, do you know if your currency code converter will work with c as well as c++?
otherwise i guess i can split it using awk or something.

many thanks anyway.

 

[bigtamscot]

I had a assignment in which i converted a double value to currency for a print report with a home made function.

void monetary_balance (double bal_val, int flag)
{
const long test1 = 100000000L, test2 = 100000L,
grand = 1000L, tun = 100L;
long under100 = 0L, under1000 = 0L, undermill = 0L,
convertval = 0L, overmill = 0L;
char minus = ' ';

if(bal_val < 0) /* negative value ?*/
{ /* converts to positive */
bal_val -= (bal_val * 2);
minus = '-'; /*minus sign for display or print */
}
bal_val *= 100;
convertval = (long)bal_val;

if(convertval >= test1) /*over 999,999.99*/
{
under100 = convertval % tun;
under1000 = convertval % test2;
under1000 = under1000 / tun;
undermill = convertval / test2;
undermill = undermill % grand;
overmill = convertval / test1;
if(flag)
printf(&quot;%c%3ld,%03ld,%03ld.%02ld&quot;, minus, overmill, undermill,
under1000, under100);
else
fprintf(prnt,&quot;%c%3ld,%03ld,%03ld.%02ld&quot;, minus, overmill,
undermill, under1000, under100);
}
else if(convertval >= test2) /*over 999.99*/
{
under100 = convertval % tun;
under1000 = convertval % test2;
under1000 = under1000 / tun;
undermill = convertval / test2;
if(flag)
printf(&quot;%c%3ld,%03ld.%02ld &quot;, minus, undermill, under1000,
under100);
else
fprintf(prnt,&quot;%c%3ld,%03ld.%02ld &quot;, minus, undermill,
under1000,under100);
}
else /*must be under 1000.00*/
{
under100 = convertval % tun;
under1000 = convertval % test2;
under1000 = under1000 / tun;
if(flag)
printf(&quot;%c %3ld.%02ld &quot;, minus, under1000, under100);
else
fprintf(prnt,&quot;%c %3ld.%02ld &quot;, minus, under1000, under100);
}
} /* end function monetary_balance */

now the parameters are a double value but no bigger than 42,000,000 (million); and a int value which determins if you want to print to the display or to file.

function call...
printf(&quot; In currency 41521213.12 is &quot;
monetary value(41521213.12, 1); /* this will print 41,521,213.12 to the display. Hoping to get certified..in C programming.

 

[bigtamscot]

Also the function works for any value from -42 million to +42 million. Hoping to get certified..in C programming.

 

[jtm111]

Here is some C++ code that converts to currency format. I didn't write it, I picked it up somewhere but it might be a good start for you:


#include <iostream>
#include <iomanip>
#include <sstream>
#include <string>

using namespace std;



string showCurrency(double dv, int width = 14)
{
// set local parameters
const string radix = &quot;.&quot;;
const string thousands = &quot;,&quot;;
const string unit = &quot;$&quot;;

// round the double value to the nearest integer
unsigned long v = (unsigned long) ((dv * 100.0) + .5);

string fmt;
string digit;

// two decimal precision at the tail
int i = -2;

// parse the value into components, put result in string fmt
do
{
if(i == 0)
{
fmt = radix + fmt;
}

if((i > 0) && (!(i % 3)))
{
fmt = thousands + fmt;
}

digit = (v % 10) + '0';
fmt = digit + fmt;
v /= 10;

i++;

} while((v) || (i < 1));


// stream the result to an ostringstream
ostringstream result;
result << unit << setw(width) << fmt.c_str() << endl;

// then return the string member of the ostringstream
return result.str();
}


int main()
{
double x = 12345678.90;

while(x > .001)
{
cout << showCurrency(x);
x /= 10.0;
}

return 0;
}

 

[migur]

one more (plain C) solution:
#include <stdio.h>
main(int argc, char *argv[]
{
char buf[80], *convert_currency();
double amnt;

amnt = 1234567.20;
printf(&quot;Amount (%.2f) %s\n&quot;, amnt,
convert_currency(amnt, buf));
}
char *convert_currency(double x, char *s)
{
char buf1[80], buf2[80], *p, *strchr();
int n, len;

sprintf(buf1, &quot;%.2f&quot;, x);
p = strchr(buf1, '.');
*p++ = 0;
len = strlen(buf1);
memset(buf2, 0, sizeof(buf2));
for(n = 1; n <= len; n++)
{
rshift(buf2);
*buf2 = *(buf1 + len - n);
if(n && ((n % 3) == 0))
{
rshift(buf2);
*buf2 = ',';
}
}
strcpy(s, buf2); strcat(s, &quot;.&quot; strcat(s, p);
return(s);
}
rshift(char s[])
{
int i;
for(i = strlen(s); i >= 0; i--)
s[i + 1] = s;
}