Shellscript to send an email to group when a file is placed in unix directory: Help needed

[surajkrhit]

Hello Team,

I am new in Shell scripting. In my day today task very often i face a basic problem in which somebody runs some job in uat without notifying others and existing work gets affected and the whole effort in the task gets spoiled.
I want if someone place the file in Unix path(We are using Tectia) then itself one mail will be sent to the group as a notification so that others will get to know who is running what.
Can we achieve this though shell script and can someone guide me to how to do this.
Even Your small help will be appreciated.
Thanks,
Suraj

 

[johnherman]

Here's something to get you started:

SENDTO=`tr -s '\n,\r' ', ' < /path/to/file-with-e-mail-addresses-one-per-line.cfg`
Attachment_Content="-a /path/to/attachment-file"
Mail_Trailer_Content="\nThere is a new file.\nAs this is an auto-generated e-mail, please do not reply to this e-mail. \n"
Mail_Content=`echo "${Mail_Trailer_Content}\n"`
echo -e "${Mail_Content}" | mailx -v ${Attachment_Content} -s "NEW FILE DETECTED" ${SENDTO}


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[PDreyer]

#!/usr/bin/ksh
export PS4='$LINENO#'
sleepsec=${2:-10}
if [ "$1" = "" ]
then
  echo "Err: Need filename as arg"
  exit 12
fi
while [ 1 ]
do
  fn="$1"
  xx=$(ls -l "$fn" 2>&1 )
  xxo="$xx"
  while [ "$xx" = "$xxo" ] || [ ! -f "$fn" ]
  do
    sleep $sleepsec
    xx=$(ls -l "$fn" 2>&1 )
  done
  ls -l "$fn" | mailx -s "$(date) got new $fn" zuser1@zmail.com,suraj@zmail.com
done