...And building upon Carp's fine solution, to preserve the readability of the "tick" mark, without dealing with the Oracle hassles of a tick mark, you can do the following:
UPDATE my_table
set name_col = replace(name_col,chr(39),chr(96)
where instr(name_col,chr(39)) > 0;
Sorry, on previous post, it should include a closing paren for the REPLACE function, to read as:
UPDATE my_table
set name_col = replace(name_col,chr(39),chr(96))
where instr(name_col,chr(39)) > 0;
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.