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Round to one decimal place based on two datetime fields

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Jdbenike

MIS
Sep 11, 2008
74
US
Code:
ROUND(convert(decimal(10,1), datediff(minute, shiftstartdate, shiftenddate) / 65.0), 1)

This code right here brings back a 7.8
The value without the round is 7.85

So, if I change the code to convert(decimal(10,2) it brings back 7.90

How do I return a value of just 7.9. shiftstartdate and shiftenddate are datetime values.
 
Is this your same question I answered in the other forum?
thread1462-1541483
 
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