REQ: Help with parsing please 2

[Kipnep70]

This is what I got so far ..

BEGIN{
        error_no=0
        while(1)

        }
                        /status error_no / {
                        error_no++
                        if(error_no==200)
                        {
                                print "End Searching " 
                                break
                        }
                        print $8
        }
}

I also am trying to work from a one-liner ...

 cat error.txt | grep status | awk '/status 1 /{a=$8;print a>"status1.txt"}'

What I am ultimately trying to do is search through a log file and sort out all the lines with a "status" string followed by a number 1 - 200. For example I want the string "status 1" to be dumped to status1.txt .. all the "status 2" strings I want dumped to a status2.txt and so forth.

anyway I'm trying to figure out how to combine the codes above to get what I want.. I know that I'm missing some stuff, but at this point I'm totally lost.

Thanks,

 

[bigoldbulldog]

Are the status and the number strings in the same columns at all times? Is the data in order? If yes, e.g. $2 & $3, then this is super easy.

awk '/status [12]/print $8 > $2 $3".txt";{if(/status 200/)exit}' error.txt

Cheers,
ND

 

[Kipnep70]

ND,

Thanks for your help.

As an example here are two lines from the error.txt that I need sorted ..

04:03:06.888 [21205] <16> log_in_errorDB: backup of client ABCclient exited with status 1 (the requested operation was partially successful)
05:02:31.193 [21205] <16> log_in_errorDB: backup of client XYZclient exited with status 41 (network connection timed out)

The result I want is that in the first line (status 1) the client name in field 8 ($8), ABCclient, will be dumped to a status1.txt text file and in the 2nd line, XYZclient dumped to a status41.txt file.

I tried running the command you told me:

awk '/status [12]/print $8 > $11 $12".txt";{if(/status 200/)exit}' error.txt

But I received the following error:

# awk '/status [12]/print $8 > $11 $12".txt";{if(/status 200/)exit}' error.txt
 syntax error The source line is 1.
 The error context is
                /status >>>  [12]/print <<<  $8 > $11 $12".txt";{if(/status 200/)exit}
 awk: Quitting
 The source line is 1.

Any advice?

I ran the following ... which produced the above error:

 

[PHV]

A starting point:
awk '$11=="status"{print $8>"status"$12".txt"}' error.txt

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[bigoldbulldog]

Oh, if you still need to filter the status number from to 1-200 then ammend the filter portion

awk '$11=="status" && $12>=1 && $12<=200 {...

Cheers,
ND