Removing CR/LF from a file

[josem]

I'm fairly new to unix. I got a data file with records that were extracted from oracle. Each of these records has a line break at the end, but I need to join all the records into one large string. (remove CR/LF)

Is there any way that I can do this from unix ??

I've tried sed 's/^M$//g ' f1 > f2

but it does not seem to work !!

any help is appreciated. code is much !! appreciated.

Thanks,
Jose

 

[MikeLacey]

Jose,

try

sed 's/^M^L//' f1 > f2

Mike
michael.j.lacey@ntlworld.com

 

[Danne]

Try tr -d, don't remeber thr syntax completly but i think it's something like this : tr -r &quot;<'15>&quot; file1 file2

 

[jdhinze]

If you edit the DOS text file with the &quot;vi&quot;
editor in UNIX, use the following from the
&quot;vi&quot; command line:

:%s/^V^M//g

From a Unix shell use the command:

% sed 's/^V^M//g' foo > foo.new

NOTE: ^V is control V and ^M is control M or Enter

 

[josem]

Thank you all for your replies. I've got the file as I wanted it.

One more question. Is it possible to remove just the Line feed from the file leaving the CR character in the file ??

 

[jad]

dos2unix? or is that the other way around?

 

[MoisDude]

I am stealing some code here!...

But see if this gives you any advantage on your problem.

Cut here
------------------------
#include <stdio.h>

void main ()
{
int ch;

/* Print all stdin */
while ((ch = getchar()) != EOF)
{
putchar(ch);

/* LF = CR + LF */
if (ch == '\n')
{
putchar('\r');
putchar('\n');
}
}
}
---------------------------
cut here

L8ter!! Life is good!, live it?