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Remove TN

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cmanalyst

Technical User
Oct 1, 2009
27
US
Hi,

Can someone please direct me on how to remove the second TN entry for this user? I used ld 20/Easy Change to add the 252 TN and it's working as expected. I need to remove the 012 TN.

Please help.

TN 012 0 09 08 V KEY 00 H MARP DES 2SE57 6 OCT 2009
(2616)


>ld 20
REQ: prt
TYPE: dnb
CUST 0
DN 1234
DATE
PAGE
DES
DN 1234
CPND
NAME JOE SMITH
XPLN 27
DISPLAY_FMT FIRST,LAST
TYPE SL1
TN 252 0 01 12 V KEY 00 H DES 2SE48 2 NOV 2009
(I2002 )
TN 012 0 09 08 V KEY 00 H MARP DES 2SE57 6 OCT 2009
(2616)
NACT
 
Hmm..almost seems too simple...will I be able to use that TN again for another user? W

Will I need to do anything special to use that TN for another user?

Sorry for my basic questions..but this is a huge learning curve for me.

Thanks.
Amad
 
1-print ludn

>ld 20
req:prt
type:ludn
cust 0
dn
.
.

2-chg dn

>ld 20
req:chg
type:2616
echg yes
tn 012 0 09 08
item key 0 scr (dn from ludn)
.
.
.

Samo
 
YOu will be able to use that TN for any other Digital Phone that your software supports. You will not be able to use it for an analog phone.

JohnThePhoneGuy

"If I can't fix it, it's not broke!
 
Ok, after this:

>ld 20
REQ: out
TYPE: 2616
TN 12 0 9 8

I am now getting this SCH0805 message: Specified TN is Invalid. Is this normal?
How am I suppsoed to re-use that TN?

>ld 20
REQ: prt
TYPE: tnb
TN 12 0 9 8
DATE
PAGE
DES
SCH0805

 
you out'd it - there is nothing to print

>ld 20
REQ: LUVU
TYPE: 2000
TN 12 0



 
You can reuse it!
Ld 11:
REQ=new
type= 2616 (or whatever digital set you need)
tn =12 0 9 8

etc etc

JohnThePhoneGuy

"If I can't fix it, it's not broke!
 
Thank you ALL dearly!

Everything is working as expected!

Amad
 
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