Regular expression ignore decimal 2

[stewartwebb]

Hi All,

I call this line of code on onKeyUp from a text box:-

myInput.value = myInput.value.replace(/\D*|./g, "")

The code works as I want it too, it removes any non numeric characters that have been entered.

Can someone let me know how I can adjust this line so that it removes non numeric characters but also ignores a decmial point?

Thanks

Stewart.

 

[feherke]

Hi

myInput.value = myInput.value.replace(/[red][^[/red]\d.[red]][/red]/g, "")

Feherke.

http://rootshell.be/~feherke/

 

[stewartwebb]

Thanks that works great.

1 more question, not sure if this is possible and sorry for not asking this in the first place, but is it possible to only allow 1 decimal point - at the moment the user can enter as many decimal points as they like?

Stewart.

 

[feherke]

Hi

That is not so simple in JavaScript with regular expressions. Must it be with that [tt]RegExp.replace()[/tt] ?

Feherke.

http://rootshell.be/~feherke/

 

[tsuji]

You may try this.
[tt] myInput.value=myInput.value.replace(/((\.[^.]*?)+)(\.)/g,"$1").replace(/[^0-9.]/g,"");[/tt]
One detail of it is to forbid the last decimal point once there are one or more than one already entered. As it is implemented in the onkeyup, it effectively forbids the second decimal period.

 

[friendlyposter]

One minor alternate suggestion to consider:

If you want to simplify work done by regular expression,
I would split the string on the decimal place character, and check the resulting array length (max 2).

Each array item can then be stripped of non-digits and the array re-joined into a string.

It is not as elegant as a regex but may be easier to maintain.

 

[stewartwebb]

Thanks very much - works perfectly - you can both have a star.

 

[adam0101]

Keep in mind that the user could still enter a number in by pasting it or selecting it from an auto-complete menu. I hope you're checking the value on the server too!

Adam

http://adameslinger.blogspot.com/