Regular expression for (1,0),(2,0),(3,0)

[hemajb]

Could anyone tell me what would be the regular expression
(1,0),(2,0),(3,0) ?? This is quiet urgent

 

[Lrnmore]

Can you explain how you are using the regular expression?

Are you just checking the pattern?

Are you checking those specific values?

And new RegExp() can be used if this is a variable
value.


2b||!2b

 

[hemajb]

Am using it this way
function checkSyntax()
{
var value = '(1,0),(2,1),(3,1),(4,0)';
regex= /^(\(\d{1,3},[0-1]\)(,{0,1}))+$/;
var nArray = value.match(regex);
if (nArray==null)
alert("not a proper pattern"
else
alert("Proper pattern"
}

value can take (1,0),(2,1),(3,0)....
The problem with this code is it works fine even when i give (1,0),(2,0),
the pattern must not end with a comma..

 

[Lrnmore]

Try,

regex= /^(\(\d{1,3},[0-1]\),{1})+(\(\d{1,3},[0-1]\))$/;

worked in my tests

2b||!2b

 

[hemajb]

My sincere thanks for the help.You solved my problem.
Cheers

 

[hemajb]

So dumb of me , i didnt check this for just (1,0). it doesnt work when there is just one sequence

 

[Lrnmore]

By using * we can tell it 0 or more where the
+ looks for one or more.

Try this:

re = /^(\(\d{1,3},[0-1]\),{1})*(\(\d{1,3},[0-1]\))$/;

2b||!2b

 

[hemajb]

Thanks, It works fine now
Regards