regexp with round brackets

[domenicodl]

Hi,
I want to replace "(" and ")" with "". Suppose that you have a string like 00(r1) I would like to have 00r1.
To this end, I wrote:

regexp = "[\)\)]";
sub(regexp,"",r);

where r is the variable where I store the string 00(r1).
With the former code, I get 00(r1) -> 00(r1
I also tried with
regexp = "/[\(\)]/"
with the same result.
Thank you in advance

 

[feherke]

Hi
[ul]
[li]No need to escape parenthesis ( () ) inside the character list.[/li]
[li][tt]sub()[/tt] will replace only the first one, use [tt]gsub()[/tt] for multiple replacements.[/li]
[/ul]

regexp="[()]"
gsub(regexp,"",r[i]))

[gray]# or[/gray]

gsub(/[()]/,"",r[i])

Tested with [tt]gawk[/tt] and [tt]mawk[/tt].


Feherke.

http://free.rootshell.be/~feherke/

 

[CaKiwi]

One way is to use 2 sub statements

sub(/\(/,"",r[i])
sub(/\)/,"",r[i])

CaKiwi

 

[domenicodl]

Perfect, thank you both