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regex, return all <a....> .... </a> from html

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gbrian

gbrian

IS-IT--Management
Sep 22, 2004
96
US
Hello,

I need to create a regular expression so that I can replace anything in an html source file with blank if it does not match the criteria <a *> *</a>

Example,
<html>
<strong><a href="asdf.com"> test1 </a></strong>
<strong><a href="asdf.com"> test2 </a></strong>
</html>

would return:
<a href="asdf.com"> test1 </a>
<a href="asdf.com"> test2 </a>

I think a regular expression would be the easiest way to do this (preg_replace)

Thanks in advance for your help.
 
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Code: 
$pattern = "/<a\b[^>]*>(.*?)</a>/";
preg_match_all($pattern, $html, $matches);
print_r($matches);

this checks for "a" and not "A". easy enough to make it case insensitive.
 
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Thanks for this, for some reason it is giving me an error:

Unknown modifier 'a' in ...

Any ideas?
 
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sorry, forgot the escaping

Code: 
<?
$html = "This is a <a href='#'>link</a> to <a href='#'>something</a>";
$pattern = "/<a\b[^>]*>(.*?)<\/a>/";
preg_match_all($pattern, $html, $matches);
print_r($matches);
?>
 
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