Regex Question

[AcidHawk]

Hi,

I am having difficulty groking this regex stuff. I have a string:
"SomeStuff D: Drive is full"

In perl I can do something like if (my $var =~ /\s{1}.:\s/) { ...} where I can check the string to see if there is any occurance of space-anyletter-colon-space

I am trying to do the same in java.. I have...

Pattern p1 = Pattern.compile("\\s\\w:\\s");
Matcher m1 = p1.matcher(myString);
if (m1.matches()) {
System.out.println("MATCH FOUND:" + m1.group(1));
System.out.println("MATCH FOUND:" + m1.group(2));
}
else {
System.out.println("NO MATCH FOUND");
}

This does NOT work.. Can any-one tell me where I am going wrong?

In group(1) I am looking for "SomeStuff" and in group(2) I am looking for "D: Drive is full"

Many thanks
AcidHawk



----
Of All the things I've lost in my life it's my mind I miss the most.

 

[sedj]

AcidHawk :

please do not crosspost (Sun Java Workshop).

I am not personally a regex man, but stefanwagner is I believe - he should be along the forums in a while I would imagine.

 

[nikw]

Hi AcidHawk,

I had a similar problem where the matches() method doesn't seem to do what you would expect. So I ended up doing something like:

Pattern p1 = Pattern.compile("\\s\\w:\\s");
Matcher m1 = p1.matcher(myString);
boolean b1 = m1.find();
if (b1) {
String[] strArr = p1.split(myString);
System.out.println(strArr[0]);
System.out.println(strArr[1]);
}
else {
System.out.println("NO MATCH FOUND");
}

I know this is not ideal but I hope it helps

Nick

 

[onpnt]

I would think you're escaping the notations here with the Pattern p1 = Pattern.compile("\\s\\w:\\s");

java should not have a issue with \s\w:\s

also if you are matching ANY occurances then use the [ ]

but if you are explicitly matching a drive then I would think

^\s(\w\s$

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[stefanwagner]

Here I am

String s = "SomeStuff D: Drive is full";
Pattern p1 = Pattern.compile("(.*) (.: .*)");
Matcher m1 = p1.matcher (s);
if (m1.matches()) 
{
	System.out.println("MATCH FOUND:" + m1.group(1));
	System.out.println("MATCH FOUND:" + m1.group(2));
}

I'm not used to \\s and \\w - they might work too.

onpnt: \s isn't a regular escape-sequence. Therefore you have to mask the \ with another \.

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[stefanwagner]

aaah - forgot to add some prosa:
To create a capturing group, you use ().
(Therefore they have to be escaped, if meant itself.)

Instead of 'Matcher, Pattern' used explicitly, you could do

System.out.println (s.replaceAll ("(.*) (.: .*)", "MATCH FOUND: $1 \nMATCH FOUND: $2"));

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http://home.arcor.de/hirnstrom/bewerbung

 

[onpnt]

Hey stefanwagner

I know \s isn't a escape-sequence. It is the special sequence for a whitespace. After doing some reminder reading (been a bit) I see that you do need the double up in java (and C# as I just found) unless you add the @.


I'm just crossing language syntax again. I'll keep it shut until I'm sure from now on


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