Really Basic but a biginner

[Cmca123]

Hi,

I'd like to pass a varaible to my perl script and then print it, is $1 correct syntax. thanks

#!/usr/bin/perl
use strict;
use warnings;
$string = $1;
print $string;

 

[Cmca123]

its okay.. solution

my $var = $ARGV[0];
print $var1;

 

[stevexff]

Alternatively

print $ARGV[0];

Steve

[small]"Every program can be reduced by one instruction, and every program has at least one bug. Therefore, any program can be reduced to one instruction which doesn't work." (Object:erlDesignPatterns)[/small]

 

[feherke]

Hi

I would never believe that works better than the first code...

my $[red]var[/red] = $ARGV[0];
print  $[red]var[b][u]1[/u][/b][/red];

Feherke.

http://rootshell.be/~feherke/