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QWERTY fun

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AnotherHiggins

Technical User
Nov 25, 2003
6,259
US
What's the longest word you can find that can be typed entirely on the top row of a standard QWERTY keyboard?

Here's one to start you off:
Code:
[white][b]typewriter[/b]   - 10 letters[/white]

[tt]_____
[blue]-John[/blue]
[/tt][red]"If you're flammable and have legs, you are never blocking a fire exit."[/red]
-Mitch Hedberg

Help us help you. Please read FAQ181-2886 before posting.
 
There is at least one ten-letter word on the top row.

gg
 
There is also a 12 letter word you can type just using the 'left-hand' keys. Any guesses?

Gez



Sorry, did I say something wrong? Pardon me for breathing which I never do anyway so I don't know why I bother to say it Oh God I'm so depressed - Marvin, Hitchhiker's Guide to the Galaxy
 
Harleyquinn, excellent! But you didn't get the word I was thinking of.

Gez



Sorry, did I say something wrong? Pardon me for breathing which I never do anyway so I don't know why I bother to say it Oh God I'm so depressed - Marvin, Hitchhiker's Guide to the Galaxy
 
That's the one. Well done!

Gez



Sorry, did I say something wrong? Pardon me for breathing which I never do anyway so I don't know why I bother to say it Oh God I'm so depressed - Marvin, Hitchhiker's Guide to the Galaxy
 
OK, another long 'top-row' word:
Code:
[white]powertrip[/white]
Gez, you beat me to the punch! Other questions: Longest word you can find typed with only:
[li]the right hand[/li]
[li]the middle row[/li]
[li]the bottom row[/li]
[li]alternating right and left hands[/li]
[li]alternating right and left hands - 2 letters at a time[/li]
The possibilities are practically endless.

Harleyquinn: nice! I couldn't come up with the other 12-letter word for the left hand.

[tt]_____
[blue]-John[/blue]
[/tt][red]"If you're flammable and have legs, you are never blocking a fire exit."[/red]
-Mitch Hedberg

Help us help you. Please read FAQ181-2886 before posting.
 
Bottom row:
Code:
[white]Kind of a trick question.  'Zzz' is all I had in mind.[/white]
Harleyquinn: that was the right hand one I was thinking of. Your alternating one is longer than the one I was thinking of ([COLOR=white white]postmuscular[/color]).

[tt]_____
[blue]-John[/blue]
[/tt][red]"If you're flammable and have legs, you are never blocking a fire exit."[/red]
-Mitch Hedberg

Help us help you. Please read FAQ181-2886 before posting.
 
What about words (phrases?) written without the middle row?

Tremor potty you,
ropey top true,
were not two but more.



BocaBurger
<===========================||////////////////|0
The pen is mightier than the sword, but the sword hurts more!
 
For what it's worth, since precision is something we all should desire, I can type any word using just my right hand. But I know what you mean when you say "words typed with only the right hand." You mean "words made only with letters supposed to be typed by the right hand." [smile]

Code:
[white]top row: peppertree, pepperwort, prerequire, repertoire, repetiteur, perpetuity, proprietor, prototropy, prototype
middle row: galahads, alfalfas

left hand: aftereffects, barebreasted, decerebrated, desegregated, desegregates, extravasated, reverberated, reverberates, watercresses

right hand: hypolimnion, homophony, homophyly, nonillion, pollinium

alternating: (the excellent "dismantlement" was already taken...) neurotoxicity, authenticity, autoantibody, cytotoxicity, leptocytosis, leucocytosis, leucocytotic, proamendment

alternating two at a time: expostulating, hydropathical, postpyramidal, hydropathies, plasmogamies, uncapitalise[/white]

For the curious, my query to select words with alternating left-hand-right-hand-supposed-to-be-typed-letters:

Code:
select
   word,
   wordlength
from
   dictionary d
   inner join numbers n on d.wordlength >= n.id
   inner join (
      select mod = 0, letter = value from dbo.Split('qwertasdfgzxcvb','')
      union select 1, value from dbo.Split('yuiophjklnm','')
   ) S on substring(word, n.id, 1) = s.letter
where wordlength >= 8
group by
   wordlength,
   word
having
   sum(abs((id % 2) - mod)) = 0
   or sum(abs((id % 2) - mod)) = wordlength
order by
   wordlength desc,
   word

-- for two at a time alternating:

having
   sum(abs((((id - 1) / 2 ) % 2) - mod)) = 0
   or sum(abs((((id - 1) / 2) % 2) - mod)) = wordlength

top row and the like was simple:

Code:
select word
from dictionary
where word not like '%[^qwertyuiop]%'
order by wordlength desc
 
From the true bottom row...

Code:
[white]cat, rat, call, tall, all[/white]

Sorry, feeling kinda spacy.

Tim

[blue]_____________________________________________________
If you need immediate assistance, please raise your hand.
If you are outside of Raleigh, raise your hand and say
[/blue] [red]Ooh! Ooh![/red]
 
Isn't this assumptive that everyone is using an English keyboard?
--Paul

cigless ...
 
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