Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations SkipVought on being selected by the Tek-Tips community for having the most helpful posts in the forums last week. Way to Go!

Query Help

Status
Not open for further replies.

V00D00

Technical User
Jul 11, 2005
78
0
0
US
Any help with this will be greatly appreciated. The table I have has a field called 'TYPE' and 'DOL' (DOL = Date of Load).

I need to produce a query that will count the number of 'TYPE' and group them by 'DOL' for a given week.

For example:


Code:
TYPE     1 WEEK OLD   2 WEEKS OLD   3 WEEKS OLD

00           53            42           12
01           43            23           12
02           12            41           43
03           0             0            1

Two problems I have run in to so far are:

1. I need to be returned a 0 count for TYPES if applicable.

2. I need the dataset to be returned in the exactly the same order each time.

If I can come up with a query that will satisfy these two problems, then I can use PERL to grab the data and produce the report in the desired output.
 
You show sample output data. Can you also show some sample input data? It will help us to help you.

-George

Strong and bitter words indicate a weak cause. - Fortune cookie wisdom
 
Code:
SELECT Type,
       SUM(CASE WHEN DateDiff(dd, DOL, GetDate()) BETWEEN 1  AND 7 THEN 1 ELSE 0 END) AS 1_WEEK_OLD,
       SUM(CASE WHEN DateDiff(dd, DOL, GetDate()) BETWEEN 8  AND 14 THEN 1 ELSE 0 END) AS 2_WEEKS_OLD,
       SUM(CASE WHEN DateDiff(dd, DOL, GetDate()) BETWEEN 9 AND 21 THEN 1 ELSE 0 END) AS 3_WEEK_OLD
FROM MyTable
GROUP BY Type
not tested



Borislav Borissov
VFP9 SP1, SQL Server 2000/2005.
MVP VFP
 


Sample Input Data.

TABLE NAME: LEADS

Code:
TYPE     DOL
01       09/01/2006
03       09/04/2006
04       09/14/2006
05       09/08/2006
02       09/11/2006
03       09/01/2006
05       09/04/2006
01       09/14/2006
00       09/08/2006
02       09/11/2006
04       08/25/2006
05       09/03/2006
 
I should add this will be a report run each sunday night and the "WEEKS OLD" will reflect how old from the day the report is run.
 
Chanemy first statment to be:
Code:
SUM(CASE WHEN DateDiff(dd, DOL, GetDate()) BETWEEN 0  AND 7 THEN 1 ELSE 0 END) AS 1_WEEK_OLD,
If you want to include current day in that report.

Borislav Borissov
VFP9 SP1, SQL Server 2000/2005.
MVP VFP
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top