Problem using "long double" data type

[unirams]

Hi,

Anyone help me to find the control string for long double. I want to print the number as it is.
I wrote the following program

main()
{
long double d;
double d1;
d1 = (double)(double)999/(double)1000;
d=(double)(123456789012345+d1);
printf("\nd=%Lf\n",d);
}

For the above program, i am expecting the following result,
123456789012345.999

But i am getting the following output.
d=123456789012346.000000

What is the problem and how i will get the expected output. Please clarify. Thanks in advance.

Regards,
Ram

 

[ankan]

Change the line...
d=(double)(123456789012345+d1);

to...
d=(double)(123456789012345.+d1);
or even...
d = 123456789012345. + d1;

Does that work??
Ankan.

Please do correct me if I am wrong. s-)

 

[ankan]

Change the line...
d=(double)(123456789012345+d1);

to...
d=(double)(123456789012345.+d1);
or even...
d = 123456789012345. + d1;

Does that work??
Ankan.

Please do correct me if I am wrong. s-)

 

[unirams]

Hi,

Thanks for your response. But the code below is working fine now.

d = 123456789012345. + (long double)d1;

Thanks and regards,
Ram

 

[smaniraja]

Hey use like this,

d = 123456789012345.0l + d1;

use a l / L following the double number, when you want to use a long double number.

Maniraja S.

 

[unirams]

Hi Maniraja,

Still it is not working. I have found the solution. Please my previous response to ankan.

Thanks
Ram