Printing Integers in NASM

[klose86]

HI everyone

I'm a newbbie in assembly, but trying to learn. Does anyone know how do I print integer values on the screen? I'm working on Linux with the NASM compiler.
I know how to print strings, like the classic "hello world!", but it doesn't work for numbers.

I defined the variables this way:

L1 db 100
L2 db 450

I want to add both numbers and the print the result.

Thank you very much

 

[Prattaratt]

You have to convert the numeric values to their representative ASCII string before printing. Developing this algorithm involves a learning process every programmer must go thru on the road to developing more complex algorithms, which is why this assignment is one of the first ones handed out by instructors. If we were to give it to you on a silver platter, you will have not learned one of the foundations of assembly prgramming. But I will give you a hint: how are ASCII character Codes stored in memory?

The simplest solution is the best!

 

[rankamateur]

I'm not familiar with NASM syntax, so I can't help you there. However, here's a short program that demonstrates how to print integers in assembly using the C function library, using Gnu Assembler syntax:

.section	.data
format:	.asciz	"L1 = %d  L2 = %d\n"
L1:	.int	100
L2:	.int	450

.section	.data
	.global	_start
	.align	4

_start:
	pushl	L2
	pushl	L1
	pushl	$format
	call	printf

	movl	$1, %eax
	int	$0x80