print line below and line above

[ng1]

I have an awk script that is getting me part of what I need. It is giving me the lines with the criteria I have specified.

{
if (($3 == 0) || (($9 == 304) || ($9 == 306)))
{ print $0 }
}

Here is what else I need to do but don't know how. In the
(($3==0) part, I ALSO need the line ABOVE that line. In the (($9 == 304) || ($9 == 306))) part, I ALSO need the line BELOW that line.

 

[feherke]

Hi

awk '$3==0||$9==304||$9==306{print p;print;getline;print}{p=$0}' /input/file

Feherke.

http://rootshell.be/~feherke/

 

[PHV]

$3==0 {print above}
$3==0 || $9==304 || $9==306
$9==304 || $9==306 {getline;print}
{above=$0}

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[ng1]

Thanks for your help. How would I put either of your scripts into a file that I can reference with awk -f ?

 

[PHV]

What I've posted is the content of an awk program file, so I quite don't understand your question.

 

[ng1]

I got it now. Thanks.