print hex value of a random number 1

[userMikeD]

I can print the hex value of a given number using printf

printf "%02x\n" 2 -> 02
printf "%02x\n" 20 -> 14
printf "%02x\n" 200 -> c8

I need to print the hex value of a random number, 0-127, but can't seem to get that working. I tried this:

printf "%02x\n" ${RANDOM}%128

What do I need to do differently?

Thanks,
Mike

 

[feherke]

Hi

Arithmetic evaluation is not one of the main tasks of a shell. If you need such thing, you have to ask for it explicitly :

[COLOR=chocolate]printf[/color] [green][i]"%02x[/i][/green][lime][i]\n[/i][/lime][green][i]"[/i][/green] [highlight][teal]$(([/teal][/highlight] [blue]RANDOM[/blue][teal]%[/teal][purple]128[/purple] [highlight][teal]))[/teal][/highlight]

Feherke.

http://free.rootshell.be/~feherke/

 

[userMikeD]

Thank you for the quick response! That did it!