PHP Windows Scheduler Task 1

[jay123454]

I'm not too familiar with setting up php Windows Scheduler tasks. So hopefully someone here can help me. Trying to setup this task in Server2003/IIS6

This is what I have for the task...but I'm getting "No Input File Specified" everytime I run this. Any ideas? Is my syntax correct?

C:\PHP\php.exe C:\mydir\autorun\statistics.phpAutorun_Pin=mypassword

 

[sleipnir214]

You're not trying to do a GET-method URL input to your script, are you? That only works through a web browser.

Instead, if you want to pass parameters to a script run from the command-prompt (which this is), you must do something like:

C:\PHP\php.exe C:\mydir\autorun\statistics.php /Autorun_Pin=mypassword

And have your script interpret $_SERVER['argc'] and $_SERVER['argv'] to figure out what parameters it's being passed at runtime.


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[jay123454]

Yes, was trying to pass a variable to the script. Now if I use REQUUEST will it work for this call and browser call?

$_REQUEST['Autorun_Pin'];


Or will I have to insert some other code to check for this?

Sorry, not familiar with
$_SERVER['argc'] and $_SERVER['argv']

Thanks!

 

[sleipnir214]

I strongly recommend that you never, ever, under any circumstances use $_REQUEST. You might as well turn on register_globals, because in terms of variable poisoning, using $_REQUEST is as insecure.

$_POST, $_GET, $_COOKIE, etc, all require that they be populated by PHP. PHP, in most cases, must be passed this information by the web server. Which you don't have available.


$_SERVER['argc'] records how many parameters were passed on the command-line when the script was invoked. $_SERVER['argv'] is an array of those arguments. If you invoke PHP from the command-line as:

[C:\new_emails]php -q test_command-line.php /foo=bar

Then $_SERVER['argv'] will contain:

Array
(
[0] => test_command-line.php
[1] => /foo=bar
)




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[jay123454]

So I'll have to parse argv for the variables I'm looking for?

$server_vars=$_SERVER['argv'];

So
//$server_vars[1]="/foo=bar&foo2=bar2";
if(strlen($server_vars[1])>0)
{
$vars=sub_str($server_vars[1], 1);
$vars=explode("&", $vars);
foreach($vars as $key => $val)
{
$$key=$val;
}
}
And then I'd have available in my script.
$foo="bar";
$foo2="bar2";


Correct?

 

[jay123454]

Also,

What if I wanted to pass 2 variables?

C:\PHP\php.exe C:\mydir\autorun\statistics.php /Autorun_Pin=mypassword /foo=bar

??? Is this how I would do it?

 

[jay123454]

Can any help out on the above 2 Q's?

Also, I was still getting errors on

C:\PHP\php.exe C:\mydir\autorun\statistics.php /Autorun_Pin=mypassword

But this worked with just a space before the variable? Which one is the correct syntax?

C:\PHP\php.exe C:\mydir\autorun\statistics.php Autorun_Pin=mypassword

Thanks!

 

[sleipnir214]

If you pass more parameters, $_SERVER['argv'] will have more items in it. But you could easily have known this through experimentation on your own.

Whether or not you put slashes, dashes or something else is entirely a stylistic question that only you can answer.


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