php redirect for two URLs

[calidude]

I am trying to set up a redirect based on the URL requested. Below is my code. I get the following error Parse error: syntax error, unexpected '(' in /vservers/mysite/htdocs/home.php on line 4.

Any idea where I am going wrong?


<?php
$domain = $_SERVER["HTTP_HOST"];
if (($domain == “myfirstdomain.com”)
($domain == “

http://www.myfirstdomain.com”))

{
header(”location:

http://www.myfirstdomain.com/photocart/index.php”);

}
if (($domain == “myseconddomain.com”)
($domain == “

http://www.myseconddoamin.com”))

{
header(”location:

http://www.myseconddomain.com”);

}
?>

 

[AdaHacker]

Well, you're missing a boolean operator in your if condition. What you've posted isn't valid syntax. You probably wanted a logical or in there.

if (($domain == "myfirstdomain.com") [COLOR=red]||[/color]
   ($domain == "[URL unfurl="true"]www.myfirstdomain.com"))[/URL] {

 

[calidude]

Hmmmm. I added the || but now I get

Parse error: syntax error, unexpected ':' in /vservers/mysite/htdocs/home.php on line 5

Thanks for the help.
Bob

 

[audiopro]

Did you add || to both of your if conditionals?

Keith

http://www.studiosoft.co.uk

 

[jpadie]

<?php 
$domain = explode ('.', $_SERVER["HTTP_HOST"]);
$domain = strtolower($domain[count($domain) - 1]);

switch ($domain){
 case 'myfirstdomain':
 $location = '[URL unfurl="true"]http://www.myfirstdomain.com/photocart/index.php';[/URL]
 break;
 case 'myseconddomain':
  $location = '[URL unfurl="true"]http://www.myseconddomain.com';//note[/URL] that there is a never ending loop here
  break;
} //end switch

if (!empty($location)) {
 header ("Location: $location");
 exit();
}
?>

 

[calidude]

I now have

Parse error: syntax error, unexpected ':' in /vservers/mydomain/htdocs/home.php on line 5


<?php
$domain = $_SERVER["HTTP_HOST"];
if (($domain == “mydomain.com”)||
($domain == “

http://www.mydomain.com”))

{
header(”location:

http://www.maydomain.com/photocart/index.php”);

}
if (($domain == “mydomain2.com”)||
($domain == “

http://www.mydomain2.com”))

{
header(”location:

http://www.mydomain2.com”);

}

?>

 

[jpadie]

you are not copy-pasting faithfully. the error you are getting derives from a mismatch in quotes, most probably in line 3 or 4. your pasted version does not show this error.

 

[calidude]

jpadie, I tried your code but only get a blank page.

 

[calidude]

ok, here is a strange one. I copied and pasted what I had posted here into my page and now it works. I have no idea why. Thanks everyone for the help.

Perplexed Bob

 

[jpadie]

for my code this line was incorrect

$domain = strtolower($domain[count($domain) - [red]2[/red]]);

and actually this is not a great way to do things if you are using a mixture of, say, .co.uk and .com domains. it would be better to use a preg_match like so:

$domain = preg_replace('/^[URL unfurl="true"]www\./i',[/URL] '', $domain);
$domain = strtolower($domain);

//and then go into the switch on the full domain name minus the [URL unfurl="true"]www bit[/URL]

 

[Foamcow]

You should modify your header() functions to include a proper response code. Probably a 301.

header("Location: [URL unfurl="true"]http://www.my-domain.com/",TRUE,301)[/URL]

However, would it not be better to do this using htaccess?

Options +All
RewriteEngine On

RewriteCond %{HTTP_HOST} ^my-domain.co.uk
RewriteRule ^(.*)$ [URL unfurl="true"]http://www\.my-domain\.co\.uk/$1[/URL] [R=permanent,L]

RewriteCond %{HTTP_HOST} ^my-other-domain.co.uk
RewriteRule ^(.*)$ [URL unfurl="true"]http://www\.my-other-domain\.co\.uk/$1[/URL] [R=permanent,L]

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