PHP array into xslt

[joseppic]

I would like to pass a list of data I have in a php array into my xslt so that I can compare elements of the array with a sequence of XML (this is actually so I can have a DDLB which has some selected elements in it).

On the xslt side, can it handle such a variable as an xslaram?

How do I access the individual elements/traverse the array?
What would the xsl:for-each look like?

Should I encode the array into XML and add it to my XML string and get it into the xslt that way?
Thanks,

Joseppic.

 

[joseppic]

Ok,

How I fixed this was I put my array of fesults into a string and passed that in.

During my xslt I test the string using the contains(value, substring) to find it in the string.

HTH

 

[piclez]

Hi Joseppic,

I'm facing the same situation. Could you provide an example of how you fixed this problem?

Also, just more information about my case, I'm using C# to pass the array or variables to the XSLT.

Thanks a lot.

Peter.

 

[joseppic]

OK,

Within my Php, I have a standard xslTranslator() method which takes in:
- The XML (string datatype, in my case the possible values of a DDLB)
- The filename.xsl (the XSLTemplate for the XML, in my case the iteration to embed the above values into a DDLB)
- A Params Array (external parameters which will also affect the XSLT but are not part of the pure XML, in my case, a csv string which lists the values previously selected in a multiple DDLB).

Params are a standard way of passing data to XSLT but they do not handle Arrays. So, I collapsed my array into a csv string so it could be passed as a single Param.

The inportant XSL command is the 'contains' which checks my parameter string.


Here's an example snippet:


<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="

http://www.w3.org/1999/XSL/Transform"

version="1.0">
<xslaram name='lostofnumbersParamString' select="'aDefaultValueNotUsed'"/>
<xsl:template match='/'>
<table>
<tr>
<td align='left'>
<xsl:apply-templates select='listofnumbers'></xsl:apply-templates>
</td>
</tr>
</table>
</xsl:template>

<xsl:template match='listofnumbers'>
<xsl:call-template name='numbersDDLB'/>
</xsl:template>

<xsl:template name="numbersDDLB">
<select name='numbersSelected[]' id='numbersSelected'>
<xsl:attribute name='size'>5</xsl:attribute>
<xsl:attribute name='multiple'>multiple</xsl:attribute>
<xsl:for-each select="xmlNumberSeq">
<xsl:sort/>
<option>
<xsl:if test="contains($lostofnumbersParamString, @anXmlNumber)">
<xsl:attribute name='selected'>selected</xsl:attribute>
</xsl:if>
<xsl:attribute name='value'><xsl:value-of select='@anXmlNumber'/></xsl:attribute>
<xsl:value-of select='@anXmlNumber'/>
</option>
</xsl:for-each>
</select>
</xsl:template>
</xsl:stylesheet>



Hope this helps,

Joseppic.