Ownership and User name....

[jstreich]

I have a program in the works, and I need to compare the user name as a string to a string entered into the computer. I've come up with a fairly sloppy way, and want to know if there is a function in the standard libraries, or a more elegant way?

 

[SupaDave]

Here is a way to do it

char username[20];
cin >> username; //getting the username
if ( !strcmpi("jstreich", command))
{
\\ do some code if the username is jstreich
}

so the strcmpi is the way to do it
I'm not sure what library you have to include, I thinkit's string.h or iostream.h

 

[glathaa]

Use the following program...

#include <iostream.h>
#include <stdlib.h>
#include <string.h>

int main()
{
char username[20];
cin >> username; //getting the username
if ( ! strcmp(username, &quot;jstreich&quot)
{
\\ do some code if the username is jstreich
}
return EXIT_SUCCESS;
}

 

[jstreich]

Errr... not, a username entered into the program, the Unix user. Say for instance there is a Unix user joe_blow ... And later you read in a series of strings, and you want to find out if his Unix logon name is the third or not...
What I was thinking of was this:

string users[4] == {jill,gorege,joe_blow,john}
system("who am i > user.temp");
ifstream fin;
fin.open("user.temp");
string me;
fin >> me;
fin.close();
if(me == users[2])
{
  //do stuff
}
else
{
  /do stuff different
}

But it seems clumbsy to require a call to en external program. Is there a standard (or not so standard) way of getting the current Unix user running the program?
Sorry, I was vauge before...

 

[glathaa]

getlogin() used to get the current user name.

Use strcmp() function to compare two strings.

For more information, see the man pages of those two functions.

 

[jstreich]

Why is everyone so big on the old C calls like strcmp()?
the overloaded == operator is much easier to type.... And it is just a wraped call to strcmp. Anywho, unistd, whoda' thunk. I suppose I should have guessed that what the function would be called, and knowen that it has a man page. I'm babling.

I did try man-ing a number of other words before my orignial post. In anycase, thanks.

 

[glathaa]

Use this program .....

#include <iostream.h>
#include <fstream.h>
#include <stdlib.h>
#include <unistd.h>
#include <string>

int main()
{
string users[4] =
{&quot;jill&quot;,&quot;gorege&quot;,&quot;joe_blow&quot;,&quot;john&quot;};
string me;

// One way of finding the user name
// system(&quot;whoami > user.temp&quot;
// ifstream fin;
// fin.open(&quot;user.temp&quot;
// fin >> me;
// fin.close();

// Another way of finding the current user name
me = getlogin();
if(me == users[2])
{
// do stuff
}
else
{
// do stuff different
}
return EXIT_SUCCESS;
}

Your code was exactly correct ... The only mistake was, you have used &quot;who am i&quot; utility which will return more info about the current user. Instead you can use &quot;whoami&quot; utility which will return the name of the current user alone.

Sorry I am a C programmer ... that is why i have asked you to use &quot;strcmp()&quot; function.

 

[PhilMumf]

You probably have solved this by now, but the following all get the user name I believe on solaris

getlogin // this is a posix function too
cuserid

anyway, copy this into a string as you suggest then compare it to the entered value. You probably don't need the following code but anyway this works on solaris and should work on everything:

string Act = getlogin();
string In;
cin >> In;

if (Act == In)
{
cout << &quot;Match&quot; << endl;
}
else
{
cout << &quot;NOPE&quot; << endl;
}