onSelect assign value to hidden input

[alsaffar]

Hi there,

I have a hidden input called (amount)

<input type='hidden' name='amount'>

and I have a select input called (amount_desc)

<select name='amount_desc'>
<option value='1'>1</option>
<option value='2'>2</option>
</select>

My aim is when an option of the select input is selected to set its value to the hidden input

So when the form is submitted, the hidden input have the selected option in the select input

Thanks in advance

 

[alsaffar]

I forgot to mention is that each input (amount) and (amount_desc) are in different form in the same page

 

[mbrooks]

<script type="text/javascript">
<!--//
function fillHidden(select) {
    document.this_form.amount.value = select;
}
//-->
</script>

<form name="this_form">

<select name="amount_desc" onChange="fillHidden(this.value)">
  <option value="1">1</option>
  <option value="2">2</option>
</select>

<input type="hidden" name="amount">
</form>

M. Brooks

http://mbrooks.info

 

[mbrooks]

Once again!

<script type="text/javascript">
<!--//
function fillHidden(select) {
    document.this_form2.amount.value = select;
}
//-->
</script>

<form name="this_form1">

<select name="amount_desc" onChange="fillHidden(this.value)">
  <option value="1">1</option>
  <option value="2">2</option>
</select>

<form name="this_form2">
<input type="hidden" name="amount">
</form>

M. Brooks

http://mbrooks.info

 

[alsaffar]

mbrooks, I love your fast response ('',)

one more question,

lets say that the hidden input in a form without a name

and I can't put a name for it

and the select input in different form

can I still change the value of the hidden input based on the selection of the select input?

Thanks in advance

 

[mbrooks]

Likely.. but it would definitely be a hack so I wouldn't recommend it.

M. Brooks

http://mbrooks.info

 

[alsaffar]

How it can be a hack if both forms in the same page!

 

[mbrooks]

lets say that the hidden input in a form without a name

You have nothing that identifies your <input type=>

M. Brooks

http://mbrooks.info