Need help with calculation!

[Smitty020]

I'm trying to perform the following calculation:

y = (x ^(1/33)) -1)
where x = 14

I'm new to C#, but aware that there is no exponents.

How can I perform this calculation in C#?

Thanks for your help!

Smitty

 

[jby1]

Use the function:

System.Math.Exp(double d)

 

[Titan5]

You can use:
Math.Pow(14,(1/33)) to get the result of 14^{1/33). There are also other math functions such as Math.Abs(..), Math.Sqrt(..) functions (methods of the class) in this Math class.

 

[jby1]

Actually, do not use

System.Math.Exp(double d)

unless you are wanting to raise e to a specified power!

Apologies for the incorrect function.

 

[benlinkknilneb]

Don't know if it's an issue, but worth mentioning:

Make sure that your 1/33 is of type double. In C++ you had to make sure of this; I don't know if .NET handles the conversion for you... but if it doesn't, you may end up with x^0 every time... not many things more frustrating to figure out than that...

Ben
A programmer was drowning. Lots of people watched but did nothing. They couldn't understand why he yelled "F1!"