Hi I typed a program in from a newbie assembly language tutorial ........i saved the file as pwrbookex.s then did the following
as pwrbookex.s -o pwrbookex.o
ld pwrbookex.o -o pwrbookex
./pwrbookex
argent777@localhost ~/assembly $ <-------nothing
echo $?
displays 0
......the above was the books way to compile and run files ^ ......my program doesnt error but well it seems to do nothing .......im sure its doing what its supposed to do as I copied and pasted the example from the book in the end ......the thing is the person in the book says to try stuff with it but I dont see how I can learn much if it isnt displaying any output in my terminal ......can someone show me how I would actually display the results of the 2 powers calculations in the terminal so I can see if the calculations are working out ok......at least if they come out completely wrong i no ive made a mistake but I get nothing ?
heres the program .......any advice greatly appreciated
redwing ....ow I am using gentoo linux with as ...i think its AT&T syntax
.section .data
.section .text
.globl _start
_start:
pushl $3 #push second argument
pushl $2 #push first argument
call power #call the function
addl $8, %esp #move the stack pointer back
pushl %eax #save the first answer before
#calling the next function
pushl $2 #push second argument
pushl $5 #push first argument
call power #call the function
addl $8, %esp #move the stack pointer back
popl %ebx #The second answer is already
#in %eax. We saved the
#first answer onto the stack,
#so now we can just pop it
#out into %ebx
addl %eax, %ebx #add them together
#result in %ebx
movl $1, %eax #exit (%ebx is returned)
int $0x80
#PURPOSE: This function is used to compute
# the value of a number raised to
# a power.
#
#INPUT: First argument - the base number
# Second argument - the power to
# raise it to
#
#OUTPUT: Will give the result as a return value
#
#NOTES: The power must be 1 or greater
#
#VARIABLES:
# %ebx - holds the base number
# %ecx - holds the power
# -4(%ebp) - holds the current result
#
# %eax is used for temporary storage
#
.type power, @function
power:
pushl %ebp #save old base pointer
movl %esp, %ebp #make stack pointer the base pointer
subl $4, %esp #get room for our local storage
movl 8(%ebp), %eax #put first argument in %eax
movl 12(%ebp), %ecx #put second argument in %ecx
movl %ebx, -4(%ebp) #store current result
power_loop_start:
cmpl $1, %ecx #if the power is 1, we are done
je end_power
movl -4(%ebp), %eax #move the current result into %eax
imul %ebx, %eax #multiply the current result by
#the base number
movl %eax, -4(%ebp) #store the current result
decl %ecx #decrease the power
jmp power_loop_start #run for the next power
end_power:
movl -4(%ebp), %eax #return value goes in %eax
movl %ebp, %esp #restore the stack pointer
popl %ebp #restore the base pointer
ret
as pwrbookex.s -o pwrbookex.o
ld pwrbookex.o -o pwrbookex
./pwrbookex
argent777@localhost ~/assembly $ <-------nothing
echo $?
displays 0
......the above was the books way to compile and run files ^ ......my program doesnt error but well it seems to do nothing .......im sure its doing what its supposed to do as I copied and pasted the example from the book in the end ......the thing is the person in the book says to try stuff with it but I dont see how I can learn much if it isnt displaying any output in my terminal ......can someone show me how I would actually display the results of the 2 powers calculations in the terminal so I can see if the calculations are working out ok......at least if they come out completely wrong i no ive made a mistake but I get nothing ?
heres the program .......any advice greatly appreciated
redwing ....ow I am using gentoo linux with as ...i think its AT&T syntax
.section .data
.section .text
.globl _start
_start:
pushl $3 #push second argument
pushl $2 #push first argument
call power #call the function
addl $8, %esp #move the stack pointer back
pushl %eax #save the first answer before
#calling the next function
pushl $2 #push second argument
pushl $5 #push first argument
call power #call the function
addl $8, %esp #move the stack pointer back
popl %ebx #The second answer is already
#in %eax. We saved the
#first answer onto the stack,
#so now we can just pop it
#out into %ebx
addl %eax, %ebx #add them together
#result in %ebx
movl $1, %eax #exit (%ebx is returned)
int $0x80
#PURPOSE: This function is used to compute
# the value of a number raised to
# a power.
#
#INPUT: First argument - the base number
# Second argument - the power to
# raise it to
#
#OUTPUT: Will give the result as a return value
#
#NOTES: The power must be 1 or greater
#
#VARIABLES:
# %ebx - holds the base number
# %ecx - holds the power
# -4(%ebp) - holds the current result
#
# %eax is used for temporary storage
#
.type power, @function
power:
pushl %ebp #save old base pointer
movl %esp, %ebp #make stack pointer the base pointer
subl $4, %esp #get room for our local storage
movl 8(%ebp), %eax #put first argument in %eax
movl 12(%ebp), %ecx #put second argument in %ecx
movl %ebx, -4(%ebp) #store current result
power_loop_start:
cmpl $1, %ecx #if the power is 1, we are done
je end_power
movl -4(%ebp), %eax #move the current result into %eax
imul %ebx, %eax #multiply the current result by
#the base number
movl %eax, -4(%ebp) #store the current result
decl %ecx #decrease the power
jmp power_loop_start #run for the next power
end_power:
movl -4(%ebp), %eax #return value goes in %eax
movl %ebp, %esp #restore the stack pointer
popl %ebp #restore the base pointer
ret